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3 years ago

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A kitchen floor has an area of 48 square feet.One tile covers 0.75 square goot.How many tiles would be needed to cover the entir

e kitchen floor ?

1 answer:

pshichka [43]3 years ago

4 0

@Texaschic101 you are correct .75 x 64 will indeed equal 48 sq feet. so your answer will be 64 tiles. hope this was of help!

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Type an equation for the following pattern! Please Help!!!

Helga [31]

Answer:

y=x+2

Step-by-step explanation:

1) Solve for m using the equation m=y2-y1/x2-x1 by plugging in any 2 coordinates from the table

2) After getting m, which is 1, you can solve for b by plugging in another coordinate. For example,the coordinate (1,3): 3=(1)1+b

3) You then solve for b, which is 2

Answer: y=x+2

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3 years ago

Which one is the answer?

soldi70 [24.7K]

Its dedpool!

the answer here is B!

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3 years ago

At one point the average price of regular unleaded gasoline was $3.41 per gallon. Assume that the standard deviation price per

Aleonysh [2.5K]

Answer:

a) $1-\frac{1}{k^2} =1- \frac{1}{2^2}= 1-0.25 = 0.75$

So we expected about 75% within two deviations from the mean

b) $1-\frac{1}{k^2} =1- \frac{1}{1.5^2}= 1-0.4444 = 0.556$

So we expected about 55.6% within 1.5 deviations from the mean

And the limits are:

$Lower = 3.41 -1.5*0.09 = 3.275$

$Upper = 3.41 +1.5*0.09 = 3.545$

c) We can calculate how many deviations we are within the mean with the limits with this formula:

$z =\frac{x-\mu}{\sigma}$

And using the lower limit we got:

$z = \frac{3.05-3.41}{0.09}=-4$

And with the upper limit we got:

$z = \frac{3.77-3.41}{0.09}=4$

So then the value of k =4 and the percentage is given by:

$1-\frac{1}{k^2} =1- \frac{1}{4^2}= 1-0.0625 = 0.9375$

Step-by-step explanation:

Previous concepts and Data given

$\mu =3.41$ reprsent the population mean

$\sigma=0.09$ represent the population standard deviation

The Chebyshev's Theorem states that for any dataset

• We have at least 75% of all the data within two deviations from the mean.

• We have at least 88.9% of all the data within three deviations from the mean.

• We have at least 93.8% of all the data within four deviations from the mean.

Or in general words "For any set of data (either population or sample) and for any constant k greater than 1, the proportion of the data that must lie within k standard deviations on either side of the mean is at least: $1-\frac{1}{k^2}$

Part a

For this case we can find the percentage required replaincg k =2 and we got:

$1-\frac{1}{k^2} =1- \frac{1}{2^2}= 1-0.25 = 0.75$

So we expected about 75% within two deviations from the mean

Part b

For this case we can find the percentage required replaincg k =2 and we got:

$1-\frac{1}{k^2} =1- \frac{1}{1.5^2}= 1-0.4444 = 0.556$

So we expected about 55.6% within 1.5 deviations from the mean

And the limits are:

$Lower = 3.41 -1.5*0.09 = 3.275$

$Upper = 3.41 +1.5*0.09 = 3.545$

Part c

We can calculate how many deviations we are within the mean with the limits with this formula:

$z =\frac{x-\mu}{\sigma}$

And using the lower limit we got:

$z = \frac{3.05-3.41}{0.09}=-4$

And with the upper limit we got:

$z = \frac{3.77-3.41}{0.09}=4$

So then the value of k =4 and the percentage is given by:

$1-\frac{1}{k^2} =1- \frac{1}{4^2}= 1-0.0625 = 0.9375$

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3 years ago

What is the greatest common factor of 8n cubed and 20 n

Phantasy [73]

The greatest common factor of 8n^3 and 20n is 4n

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Jimmy applied the distributive property to write the equation below.

grigory [225]

The answer to this is 4. jimmy wrote two expressions that are not equivalent. hope this helps.

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3 years ago