Answer:
WX = 8 mm
Step-by-step explanation:
To be able to solve for WX, we need to first find the size of angle .
We use the law of sines in the blue triangle to do such:
Now we can use this value in the larger right angle triangle where WX is the opposite side to angle , and the 20 mm side is the hypotenuse:
which rounded to the nearest integer gives
WX = 8 mm
*See diagram in the attachment
Answer:
27 inches
Step-by-step explanation:
Combined perimeter = perimeter of rectangle + perimeter of triangle = 63 inches
Perimeter of rectangle = 2(L + W)
L = 11 in.
W = 7 in.
Perimeter of rectangle = 2(11 + 7) = 36 in.
Let perimeter of the triangle be represented by x
Therefore:
36 + x = 63
Subtract 36 from each side
x = 63 - 36
x = 27
Perimeter of triangle = 27 inches
Attendance with the higher ticket price is ...
... $1750/$7 = 250
So the percentage change in attendance is ...
... change = (new - original)/original × 100%
... = (250 -300)/300 × 100% = -1/6×100% ≈ -17%
Answer:
Step-by-step explanation:
From the given information:
The diagrammatic interpretation of what the question is all about can be seen in the diagram attached below.
Now, let V(x) be the time needed for the runner to reach the buoy;
∴ We can say that,
In order to estimate the point along the shore, x meters from B, the runner should stop running and start swimming if he want to reach the buoy in the least time possible, then we need to differentiate the function of V(x) and relate it to zero.
i.e
The differential of V(x) = V'(x) =0
=
squaring both sides; we get
By cross multiplying; we get
Answer:
74.5°
Step-by-step explanation:
Hannah, the kite and Patricia form the vertices of a right-angled triangle with the hypotenuse side the length of the string L = 60 feet and adjacent side the distance between Hannah and Patricia = d = 16 feet.
Let the angle between the string and the sand be Ф.
By trigonometric ratios,
cosФ = adjacent/hypotenuse
= d/L
= 16 feet/60 feet
= 0.2667
Ф = cos⁻¹(0.2667)
= 74.53°
≅ 74.5°
So, he angle between the string and the sand is Ф = 74.5°