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OverLord2011 [107]
2 years ago
13

Determine the X- and Y- intercepts for the graph defined by the given equation. Y= -8

Mathematics
2 answers:
USPshnik [31]2 years ago
8 0

Answer: Y = -8 simply means for every x coordinate the y coordinate is -8, therefore it creates a horizontal line at y = -8.

X intercepts are when y = 0. Y intercepts are when x = 0.

In this case of the line, y = -8 there is no x intercept because y doesn’t equal 0.

However there is a y intercept at (0,-8) because y is -8 for every input including 0.

Step-by-step explanation:

Hope this helps!!

Cloud [144]2 years ago
4 0
Y = -8 simply means for every x coordinate the y coordinate is -8, therefore it creates a horizontal line at y = -8.

X intercepts are when y = 0. Y intercepts are when x = 0.

In this case of the line, y = -8 there is no x intercept because y doesn’t equal 0.

However there is a y intercept at (0,-8) because y is -8 for every input including 0.

If you have any other questions feel free to ask.
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Which of the following are solutions to the equation below?
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\qquad\qquad\huge\underline{{\sf Answer}}

Let's solve the given equation ~

\qquad \tt \dashrightarrow \:4 {x}^{2}  + 20x + 25 = 49

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\qquad \tt \dashrightarrow \:4 {x}^{2}  + 20x - 24 = 0

\qquad \tt \dashrightarrow \:4( {x}^{2}  + 5x - 6) = 0

\qquad \tt \dashrightarrow \: {x}^{2}  + 5x - 6 = 0

\qquad \tt \dashrightarrow \: {x}^{2}  + 6x - x - 6 = 0

\qquad \tt \dashrightarrow \:x(x + 6) - 1(x + 6) = 0

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The position of an object at time t is given by s(t) = -4 - 2t. Find the instantaneous velocity at t = 6 by finding the derivati
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4 0
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Read 2 more answers
Which graph represents the function f (x) = StartFraction 5 minus 5 x squared Over x squared EndFraction? On a coordinate plane,
trapecia [35]

9514 1404 393

Answer:

2. On a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrants 1 and 4, and the other curve opens up and to the left in quadrants 2 and 3

Step-by-step explanation:

Technically, the curve is not a hyperbola. A hyperbola is of the form 1/x; this one is of the form 1/x².

The function can be simplified to ...

  f(x) = 5/x² -5

which is a "hyperbola" with a vertical asymptote at x=0 and a vertical translation of -5 units to bring parts of it into the 3rd and 4th quadrants.

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3 years ago
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