The school band had 2 shows last week. The first show had 400 people attending. The second show had 100 people attending. Which
2 answers:
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The given quadratic describes a parabola that opens upward. Its one absolute extreme is a minimum that is found at x = -3/2. The value of the function there is
(-3/2 +3)(-3/2) -1 = -13/4
The one relative extreme is a minimum at (-1.5, -3.25).
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For the parabola described by ax² +bx +c, the vertex (extreme) is found where
x = -b/(2a)
Here, that is x=-3/(2·1) = -3/2.
(-3/2 +3)(-3/2) -1 = -13/4
The one relative extreme is a minimum at (-1.5, -3.25).
_____
For the parabola described by ax² +bx +c, the vertex (extreme) is found where
x = -b/(2a)
Here, that is x=-3/(2·1) = -3/2.
Answer:
{x∈R | , x∉Z}
Step-by-step explanation:
Given the function y=3tan(2/3x)
We know that tangent is a function that's continuous within it's domain but not continuous on all real numbers
Also, the roots of y=3tan(2/3x) is where n is an integer
Note that the domain of the function cannot be within
Therefore, {x∈R | , x∉Z}