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3 years ago

How does dating violence affect health? Click all that apply.

Mathematics

2 answers:

Furkat [3]3 years ago

8 0

Answer:

b. c. d

Step-by-step explanation:

irina [24]3 years ago

4 0

Answer:

Some teens are at greater risk than others.

For example, youth who are victims of teen dating violence are more likely to experience symptoms of depression and anxiety. Engage in unhealthy behaviors, like using tobacco, drugs, and alcohol. Exhibit antisocial behaviors, like lying, theft, bullying, or hitting.

Step-by-step explanation:

Yes all 3 you choose are correct

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PLEASE HELP ILL GIVE BRAINLIEST

Sidana [21]

Answer:

Option C is equal to 7^1/3

5 0

2 years ago

1 Example of linear absolute value equation & linear absolute value inequality

krek1111 [17]

Example:
Linear absolute value inequalities all have a similar equation of |ax + b| < c, except they can be less than, greater than, less than or equal to, or greater than or equal to.
Hope this helped :)

5 0

4 years ago

Think I know this one but could do with some help

Andrei [34K]

Quick note: Since Riona wants to sell like 90 or 100 the answer I got was for 95.

I hope this helps you but the answer would be approximately about 83125.

7 0

3 years ago

A contractor is required by a county planning department to submit one, two, three, four, or five forms (depending on the nature

Westkost [7]

Answer:

(a) The value of k is $\frac{1}{15}$ .

(b) The probability that at most three forms are required is 0.40.

(d) $P(y)=\frac{y^{2}}{50} ;\ y=1, 2, ...5$ is not the pmf of y.

Step-by-step explanation:

The random variable Y is defined as the number of forms required of the next applicant.

The probability mass function is defined as:

$P(y) = \left \{ {{ky};\ for \ y=1,2,...5 \atop {0};\ otherwise} \right$

(a)

The sum of all probabilities of an event is 1.

Use this law to compute the value of k.

$\sum P(y) = 1\\k+2k+3k+4k+5k=1\\15k=1\\k=\frac{1}{15}$

Thus, the value of k is $\frac{1}{15}$ .

(b)

Compute the value of P (Y ≤ 3) as follows:

$P(Y\leq 3)=P(Y=1)+P(Y=2)+P(Y=3)\\=\frac{1}{15}+\frac{2}{15}+ \frac{3}{15}\\=\frac{1+2+3}{15}\\ =\frac{6}{15} \\=0.40$

Thus, the probability that at most three forms are required is 0.40.

(c)

Compute the value of P (2 ≤ Y ≤ 4) as follows:

$P(2\leq Y\leq 4)=P(Y=2)+P(Y=3)+P(Y=4)\\=\frac{2}{15}+\frac{3}{15}+\frac{4}{15}\\ =\frac{2+3+4}{15}\\ =\frac{9}{15} \\=0.60$

Thus, the probability that between two and four forms (inclusive) are required is 0.60.

(d)

Now, for $P(y)=\frac{y^{2}}{50} ;\ y=1, 2, ...5$ to be the pmf of Y it has to satisfy the conditions:

$P(y)=\frac{y^{2}}{50}>0;\ for\ all\ values\ of\ y \\$
$\sum P(y)=1$

Check condition 1:

$y=1:\ P(y)=\frac{y^{2}}{50}=\frac{1}{50}=0.02>0\\y=2:\ P(y)=\frac{y^{2}}{50}=\frac{4}{50}=0.08>0 \\y=3:\ P(y)=\frac{y^{2}}{50}=\frac{9}{50}=0.18>0\\y=4:\ P(y)=\frac{y^{2}}{50}=\frac{16}{50}=0.32>0 \\y=5:\ P(y)=\frac{y^{2}}{50}=\frac{25}{50}=0.50>0$

Condition 1 is fulfilled.

Check condition 2:

$\sum P(y)=0.02+0.08+0.18+0.32+0.50=1.1>1$

Condition 2 is not satisfied.

Thus, $P(y)=\frac{y^{2}}{50} ;\ y=1, 2, ...5$ is not the pmf of y.

7 0

3 years ago

One of the corners of a rectangle is shown.

tensa zangetsu [6.8K]

Answer:

70 degrees

Step-by-step explanation:

rectange angle total = 360

1 corner = 90

90-20 = 70

8 0

2 years ago

How does dating violence affect health? Click all that apply. ​

How does dating violence affect health? Click all that apply.