685-85=600
1 year =12 months
12 multiply by 2 =24
600 divided by 24=25
answer=25
Let us take 'a' in the place of 'y' so the equation becomes
(y+x) (ax+b)
Step-by-step explanation:
<u>Step 1:</u>
(a + x) (ax + b)
<u>Step 2: Proof</u>
Checking polynomial identity.
(ax+b )(x+a) = FOIL
(ax+b)(x+a)
ax^2+a^2x is the First Term in the FOIL
ax^2 + a^2x + bx + ab
(ax+b)(x+a)+bx+ab is the Second Term in the FOIL
Add both expressions together from First and Second Term
= ax^2 + a^2x + bx + ab
<u>Step 3: Proof
</u>
(ax+b)(x+a) = ax^2 + a^2x + bx + ab
Identity is Found
.
Trying with numbers now
(ax+b)(x+a) = ax^2 + a^2x + bx + ab
((2*5)+8)(5+2) =(2*5^2)+(2^2*5)+(8*5)+(2*8)
((10)+8)(7) =(2*25)+(4*5)+(40)+(16)
(18)(7) =(50)+(20)+(56)
126 =126
Option B:
The 12th term is 354294.
Solution:
Given data:
and 
To find 
The given sequence is a geometric sequence.
The general term of the geometric sequence is 
.
If we have 2 terms of a geometric sequence 
and 
(n > K),
then we can write the general term as 
.
Here we have and .
So, n = 7 and k = 4 ( 7 > 4)
This can be written as
Taking cube root on both sides of the equation, we get
r = 3
Hence the 12th term of the geometric sequence is 354294.
