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quester [9]
3 years ago
10

Solve by substitution 1. 6x+ 5y=7 x-y=3 2. 3a +2b =4 2a + b=6 3. 2x + y= 4 4x -y=2

Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
8 0

Answer:

1. y = 11

x = -48

2. a =8

b= -10

3. x= 1

y= 2

Step-by-step explanation:

1 . 6x + 5y = 7

x-y= 3

6x+5y = 7

6x-6y =18

-1y = - 11

6x + 5y = 7

y = 11

6x + 55 = 7

6x = -48

x = -48

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Delicious77 [7]
Mrs. Annie went to a store, spent half of her money and then $10 more. She went to a second store, spent half of her remaining money and then $10 more. But she then had no money left. How much money did she have to begin with when she went to the first store?
Answer: $60
7 0
3 years ago
LCM of x<sup>2</sup>+5x+6 and x<sup>2</sup>-x-6 is ………………………
sergejj [24]

Answer:

(x^2 - 9)(x + 2)

Step-by-step explanation:

Given:

x^2 + 5x + 6

x^2 - x - 6

Required:

LCM of the polynomials

SOLUTION:

Step 1: Factorise each polynomial

x^2 + 5x + 6

x^2 + 3x + 2x + 6

(x^2 + 3x) + (2x + 6)

x(x + 3) + 2(x + 3)

(x + 2)(x + 3)

x^2 - x - 6

x^2 - 3x +2x - 6

x(x - 3) + 2(x - 3)

(x + 2)(x - 3)

Step 2: find the product of each factor that is common in both polynomials.

We have the following,

x^2 + 5x + 6 = (x + 2)(x + 3)

x^2 - x - 6 = (x + 2)(x - 3)

The common factors would be: =>

(x + 2) (this is common in both polynomials, so we would take just one of them as a factor.

(x + 3) and,

(x - 3)

Their product = (x - 3)(x + 3)(x +2) = (x^2 - 9)(x + 2)

4 0
3 years ago
Clayton has $500 in his retirement account, and Jason has $400 in his. Clayton is adding $10 per day, whereas Jason is contribut
daser333 [38]

Answer:

$1000

Step-by-step explanation:

We can form an equation for Clayton's account: C = 500 + 10x

We can form an equation for Clayton's account:  J = 400 +12x  

(where x is the number of days)

When the two accounts will contain the same amount, it means: C = J

<=> 500 + 10x  = 400 +12x  

<=> x =50

After 50 days, there accounts will be balance. Then, we substitue x into any of the 2 equation to find out the amount: 500 + 10(50) = $1000

6 0
3 years ago
If a polynomial function f(x) has roots -9 and 7-i, what must be a factor of f(x)
Likurg_2 [28]

Hello from MrBillDoesMath!

Answer:

x + 9 and (x + ( i - 7)) are factors

Discussion:

If f(x) has roots -9 and 7-i then

f(x) = g(x)(x - (-9))  (x - (7-i))            ( g(x) is a polynomial of degree less than f(x))

That is, x + 9 and (x + ( i - 7)) are factors of f(x)

BTW: if the coefficients of f(x) are real (not stated in the Question) then the conjugate of 7-i, i.e. 7 + i, is  also be a root.

Thank you,

MrB

3 0
3 years ago
Read 2 more answers
Insert one term between -13 and -119 to create an arithmetic sequence of three terms.
daser333 [38]

Answer:

-66

Step-by-step explanation:

- 13, ____, -119

first, find the common difference:

-13 - (-119) = 106

next, divide 106 by 2: \frac{106}{2} = 53

so, the common difference is 53.

now, subtract 53 from -13:

-13 - 53 = -66

5 0
2 years ago
Read 2 more answers
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