The graph shows a
piecewise function, meaning that different functions are shows at different intervals (ranges of x-values).
1) One of the graphs is part of a parabola, meaning the equation is quadratic (has

). That equation must be

.
2) The other graph is a straight line, meaning it must be a linear equation. That equation must be x + 4.
Looking at the entire graph, you can see that the parabola starts from the left and ends with an open circle at x=2. An open circle means that the graph doesn't have a value at that point, x=2. The linear line starts with a filled point at x=2 and continues to the right. That means we're looking for the choice where:
1)

Since x=2 cannot be a point in the graph, and less than 2 means that the graph includes everything to the left of 2, but not including 2
2)

Since x=2 is a point in the graph, and greater than or equal to 2 means that the graph includes 2 and everything to the right of it
------
Answer: C)
Answer:
True
Step-by-step explanation:
the graph makes a loop and both ends go in the same direction
Log(7x+1) - log(x-2) =1
log[(7x+1) / (x-2)] =1 or log[(7x+1) / (x-2)] =log10 (log10=1)
it means (7x+1) / (x-2) =10
Solving ===> x=7
Which means she ran 4160 miles long
if this isn't the answer you wanted, please be more precise
Answer:
y = 6x + 0
Step-by-step explanation:
Equation of a line
y = mx + c
Given
( 0 , 0) ( -1/2 , -3)
find the slope m
m = y2 - y1 / x2 - x1
x1 = 0
y1 = 0
x2 = -1/2
y2 = -3
Insert the values
m = y2 - y1 / x2 - x1
m = -3 - 0 / -1/2 - 0
= -3/-1/2
Minus cancels minus
= 3/1/2
= 3/1 ÷ 1/2
= 3/1 × 2/1
= 6/1
= 6
m = 6
Substitute any of the two points given into the equation of a line
y = mx + c
Where
y - intercept point y
x - intercept point x
m - slope of the line
c - intercept
(-1/2 , -3)
x = -1/2
y = -3
-3 = 6(-1/2) + c
-3 = -6/2 + c
-3 = -3 + c
-3 + 3 = c
c = 0
y = 6x + 0
The equation of the line is
y = 6x + 0