Answer:
C) (-1, -4) and (4, 6)
Step-by-step explanation:
![\textsf{Equation 1}:y=2x-2](https://tex.z-dn.net/?f=%5Ctextsf%7BEquation%201%7D%3Ay%3D2x-2)
![\textsf{Equation 2}:y=x^2-x-6](https://tex.z-dn.net/?f=%5Ctextsf%7BEquation%202%7D%3Ay%3Dx%5E2-x-6)
Substitute Equation 1 into Equation 2 and solve for x:
![\implies 2x-2=x^2-x-6](https://tex.z-dn.net/?f=%5Cimplies%202x-2%3Dx%5E2-x-6)
![\implies x^2-3x-4=0](https://tex.z-dn.net/?f=%5Cimplies%20x%5E2-3x-4%3D0)
Find two numbers that multiply to -4 and sum to -3: -4 and 1
Rewrite the middle term as the sum of these two numbers:
![\implies x^2-4x+x-4=0](https://tex.z-dn.net/?f=%5Cimplies%20x%5E2-4x%2Bx-4%3D0)
Factorize the first two terms and the last two terms separately:
![\implies x(x-4)+1(x-4)=0](https://tex.z-dn.net/?f=%5Cimplies%20x%28x-4%29%2B1%28x-4%29%3D0)
Factor out the common term
:
![\implies (x+1)(x-4)=0](https://tex.z-dn.net/?f=%5Cimplies%20%28x%2B1%29%28x-4%29%3D0)
![\implies (x+1)=0 \implies x=-1](https://tex.z-dn.net/?f=%5Cimplies%20%28x%2B1%29%3D0%20%5Cimplies%20x%3D-1)
![\implies (x-4)=0 \implies x=4](https://tex.z-dn.net/?f=%5Cimplies%20%28x-4%29%3D0%20%5Cimplies%20x%3D4)
Substitute the found values of x into Equation 1 and solve for y:
![x=-1 \implies y=2(-1)-2=-4](https://tex.z-dn.net/?f=x%3D-1%20%5Cimplies%20y%3D2%28-1%29-2%3D-4)
![x=4 \implies y=2(4)-2=6](https://tex.z-dn.net/?f=x%3D4%20%5Cimplies%20y%3D2%284%29-2%3D6)
Therefore, the solution to the system of equations is:
(-1, -4) and (4, 6)
6 3/4 pieces, but if you just want a whole number then 6
Answer:
Hope this helps I'm not sure if its correct though, it must be correct anyway. So yea.
Answer:
The solution is x=-6 and y=7
Step-by-step explanation:
Given equations are:
![4x+4y =4\\3x+4y = 10](https://tex.z-dn.net/?f=4x%2B4y%20%3D4%5C%5C3x%2B4y%20%3D%2010)
In elimination method, the co-efficient of one of the variables are equated so that one variable can be eliminated by adding or subtracting the equations
In the given system of equations, the co-efficient of y is already same i.e. 4 so we only have to subtract the equations
Subtracting equation 2 from equation 1
![4x+4y-(3x+4y) = 4-10\\4x+4y-3x-4y = -6\\4x-3x = -6\\x = -6](https://tex.z-dn.net/?f=4x%2B4y-%283x%2B4y%29%20%3D%204-10%5C%5C4x%2B4y-3x-4y%20%3D%20-6%5C%5C4x-3x%20%3D%20-6%5C%5Cx%20%3D%20-6)
Putting x = -6 in equation 1
![4(-6)+4y = 4\\-24+4y = 4\\4y = 4+24\\4y = 28\\\frac{4y}{4} = \frac{28}{4}\\y = 7](https://tex.z-dn.net/?f=4%28-6%29%2B4y%20%3D%204%5C%5C-24%2B4y%20%3D%204%5C%5C4y%20%3D%204%2B24%5C%5C4y%20%3D%2028%5C%5C%5Cfrac%7B4y%7D%7B4%7D%20%3D%20%5Cfrac%7B28%7D%7B4%7D%5C%5Cy%20%3D%207)
Hence
The solution is x=-6 and y=7
Answer:
ok so it would take more effort to lift the 1 newton that is 4 m
Step-by-step explanation:
Work is done when a an object with a certain weight is moved at a given distance;
It is the product of force and distance and therefore varies directly to both distance and force.
Work = Force × distance;
For a 4 N box 0.5 m;
Work = 4 × 0.5
= 2 Joules
For a 1 N box 4 m
Work = 1 × 4
= 4 Joules
Therefore, Lifting a 1 N box for 4 m, will take more work
hope this helps
~ukiahsmith1
P.S pls mark brianliest
have a nice day :D