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wariber [46]
3 years ago
9

Recall the chapter example which described the fact that the mean IQ in large, diverse populations is 100 and the standard devia

tion is 15. Your sample of 300 members of your community gave you a mean IQ score of 108. Calculate the margin of error for the 99% confidence level for this sample. Which of the following figures comes closest to your answer?
A. 10.95.
B. ±1.96.
C. 12.23.
D. 11.16.
E. None of the above
Mathematics
1 answer:
vova2212 [387]3 years ago
7 0

Answer:

The margin of error for the 99% confidence level for this sample is ±2.23.

None of the given figures is close to the answer:

E. None of the above

Step-by-step explanation:

margin of error (ME) around the mean can be calculated using the formula

ME=\frac{z*s}{\sqrt{N} } where

  • z is the corresponding statistic of the 99% confidence level (2.576)
  • s is the population IQ standard deviation (15)
  • N is the sample size (300)

Using these numbers we get:

ME=\frac{2.576*15}{\sqrt{300} }  ≈ 2.23

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A teacher has 3 hours to grade all the papers submitted by the 35 students in her class. She gets through the first 5 papers in
Andreyy89
So, she has 3hrs to grade all papers, for 35 students.. alrite.

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now if we take 1/6 as the 100%, what is 1/5 in percentage then?

\bf \begin{array}{ccllll}
rate&\%\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
\frac{1}{6}&100\\\\
\frac{1}{5}&x
\end{array}\implies \cfrac{\frac{1}{6}}{\frac{1}{5}}=\cfrac{100}{x}\implies \cfrac{1}{6}\cdot \cfrac{5}{1}=\cfrac{100}{x}\implies \cfrac{5}{6}=\cfrac{100}{x}
\\\\\\
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