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2 years ago

What steps would you do to solve 3x – 5 ≥ -12?

Mathematics

1 answer:

alekssr [168]2 years ago

7 0

Answer:

D.)

Step-by-step explanation:

In order to solve you would need to first get the number with the variable by itself. So first we'd need to add 5 to the other side and we would add it bc when we move a number over the equals sign (which is what were considering the greater than sign to solve)

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How do I find 2/3 of 12 slices of pizza eaten

MariettaO [177]

Multiply 12 slices by 2/3:

12 x 2/3 = (12 x 2) /3 = 24/3 = 8

The answer is 8

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3 years ago

Read 2 more answers

Which angles are supplementary to each other?

Rus_ich [418]

Answer:

Angle 4 and Angle 1 are supplementary to each other.

Step-by-step explanation:

A line is 180°. Because angle 4 and angle 1 and right next to each other and they share a straight line, both of their angles should add up to 180°, making these two angles supplementary.

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2 years ago

Bharat has two identical ink pens with full ink. He used 3/4th of the ink from the first pen and 2/3rd of the ink from the secon

Leno4ka [110]

Answer:

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Step-by-step explanation:

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3 years ago

The GPA you earn in a particular semester is your ________ GPA, and your cumulative GPA for all completed semesters is your __

Mariulka [41]

Answer:

The GPA you earn in a particular semester is your Marginal GPA, and your cumalative GPA for all completed semesters is your average GPA.

Step-by-step explanation:

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3 years ago

Given the function h(x) =1/3 |x-6| +4, evaluate the function when x = - 3, - 2, and 0

Masja [62]

|x| = x for x ≥ 0

examples:

|3| = 3; |0.56| = 0.56; |102| = 102

|x| = -x for x < 0

examples:

|-3| = -(-3) = 3; |-0.56| = -(-0.56) = 0.56; |-102| = 102

--------------------------------------------------------------------------------

Use PEMDAS:

P Parentheses first

E Exponents (ie Powers and Square Roots, etc.)

MD Multiplication and Division (left-to-right)

AS Addition and Subtraction (left-to-right)

--------------------------------------------------------------------------------

$h(x)=\dfrac{1}{3}|x-6|+4$

Put the values of x to the equation of the function h(x):

$x=-3\to h(-3)=\dfrac{1}{3}|-3-6|+4=\dfrac{1}{3}|-9|+4=\dfrac{1}{3}(9)+4=3+4=7\\\\x=-2\to h(-2)=\dfrac{1}{3}|-2-6|+4=\dfrac{1}{3}|-8|+4=\dfrac{1}{3}(8)+4=\dfrac{8}{3}+\dfrac{12}{3}=\dfrac{20}{3}\\\\x=0\to h(0)=\dfrac{1}{3}|0-6|+4=\dfrac{1}{3}|-6|+4=\dfrac{1}{3}(6)+4=2+4=6$

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3 years ago