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ICE Princess25 [194]

2 years ago

14

What steps would you do to solve 3x – 5 ≥ -12?

1 answer:

alekssr [168]2 years ago

7 0

Answer:

D.)

Step-by-step explanation:

In order to solve you would need to first get the number with the variable by itself. So first we'd need to add 5 to the other side and we would add it bc when we move a number over the equals sign (which is what were considering the greater than sign to solve)

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Please help me i beg you!!! 30 points!!!

Westkost [7]

The third is because the prove is x = fifteen and if a number is next to a letter, it means multiply, sorry I could only do one.

6 0

3 years ago

Read 2 more answers

Factorise 9w² - 100<br><br><br>

ohaa [14]

Answer:

$9\, w^{2} - 100 = (3\, w - 10) \, (3\, w + 10)$ .

Step-by-step explanation:

Fact:

$\begin{aligned} & (a - b)\, (a + b)\\ =\; & a^{2} + a\, b - a\, b - b^{2} \\ =\; & a^{2} - b^{2} \end{aligned}$ .

In other words, $(a^{2} - b^{2})$ , the difference of two squares in the form $a^{2}$ and $b^{2}$ , could be factorized into $(a - b)\, (a + b)$ .

In this question, the expression $(9\, w^{2} - 100)$ is the difference between two terms: $9\, w^{2}$ and $100$ .

$9\, w^{2}$ is the square of $3\, w$ . That is: $(3\, w)^{2} = 9\, w^{2}$ .
On the other hand, $10^{2} = 100$ .

Hence:

$9\, w^{2} - 100 = (3\, w)^{2} - (10)^{2}$ .

Apply the fact that $a^{2} - b^{2} = (a - b) \, (a + b)$ to factorize this expression. (In this case, $a = 3\, w$ whereas $b = 10$ .)

$\begin{aligned}& 9\, w^{2} - 100 \\ =\; & (3\, w)^{2} - (10)^{2} \\ = \; & (3\, w - 10)\, (3\, w + 10)\end{aligned}$ .

8 0

3 years ago

A new LED light bulb uses 10 watts of power. Since energy = power × time , then the energy used for this light bulb can be found

sergiy2304 [10]

9514 1404 393

Answer:

150 Wh

Step-by-step explanation:

We know the energy per bulb is 10 Wh per hour, so the total energy used by 3 bulbs in 5 hours is ...

(10 Wh/(bulb·hour))×(3 bulbs)×(5 hours) = 10·3·5 Wh = 150 Wh

5 0

3 years ago

The estimated velocity v (in miles per hour) of a car at the end of a drag race is v=234\sqrt[3]{p/w} , where p is the horsepowe

Dennis_Churaev [7]

Answer:

299 miles per hour

Step-by-step explanation:

$v=\frac{234}{\sqrt[3]{\frac{p}{w}}}$

$v=\frac{234}{\sqrt[3]{\frac{1311}{2744}}}$

$v\approx299$

Therefore, the velocity of the car at the end of a drag race is 299 miles per hour

8 0

3 years ago

The weight of oranges growing in an orchard is normally distributed with a mean weight of 3.5 oz. and a standard deviation of 0.

Andreas93 [3]

Answer:

(3 oz ; 4oz)

Step-by-step explanation:

Given that :

Mean = 3.5 oz

Standard deviation = 0.5 oz

According to the empirical rule ; 68% is 1 standard deviation from the mean.

Hence, the interval that would represent the middle 68% will be:

(3.5 oz - 0.5 oz) ; (3.5 oz + 0.5oz)

(3 oz ; 4oz)

7 0

3 years ago