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Alexus [3.1K]
2 years ago
11

Find the slope of the line passing through the two points (-2,1) (6,-1)

Mathematics
1 answer:
VashaNatasha [74]2 years ago
7 0

Answer:

-1/4

Step-by-step explanation:

We use the formula:

\frac{y₂ -y₁}{x₂ -x₁}

plugging in we have

\frac{ (- 1)-(1)}{(6) -( - 2)}  =  \frac{ - 2}{8}  =  -  \frac{1}{4}

Therefore our slope is -1/4

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Mr. Jamison deposited $100 into a new savings account on January 1. On the first day of each month thereafter, he deposited thre
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Answer:

$36 400

Step-by-step explanation:

Step 1

The first step is to figure out how much money is saved at the end of each month for the period from January 1 to June 15. The amount deposited at the end of each month is obtained by multiplying the amount from the previous month by 3.

The amount deposited in January is  \$100.

The amount deposited in February is 1\$00\times 3= \$300.

The amount deposited in March is  \$300\times 3= \$900.

The amount deposited in April is  \$900\times 3= \$2\700.

The amount deposited in May is  \$2\,700\times 3= \$8\,100.

The amount deposited in June is  \$8\,100\times 3= \$24\,300.


Step 2

The next step is to add up all the money that was deposited into the account. This calculation is shown below,

\$100+\$300+900+\$\$2\,700+\$8\,100+\$24\,000=\$36\,400


5 0
3 years ago
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Zielflug [23.3K]

Answer:

512cm³

Step-by-step explanation:

Volume=512cm³

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On a unit circle, the vertical distance from the x-axis to a point on the perimeter of the circle is twice the horizontal distan
swat32

Check the picture below.

since the vertical distance, namely the y-coordinate, is twice as much as the horizontal, then if the horizontal is "x", the vertical one must be 2x.

let's find the hypotenuse first.

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\bf sin(\theta )=\cfrac{\stackrel{opposite}{2~~\begin{matrix} x \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }}{\stackrel{hypotenuse}{~~\begin{matrix} x \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ \sqrt{5}}}\implies \stackrel{\textit{and rationalizing the denominator}~\hfill }{\cfrac{2}{\sqrt{5}}\cdot \cfrac{\sqrt{5}}{\sqrt{5}}\implies \cfrac{2\sqrt{5}}{(\sqrt{5})^2}\implies \cfrac{2\sqrt{5}}{5}}

5 0
4 years ago
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Vera_Pavlovna [14]

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Step-by-step explanation:

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