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Vladimir79 [104]

2 years ago

11

The local newspaper has letters to the editor from

1 answer:

swat322 years ago

6 0

Answer:

300 readers

Step-by-step explanation:

60/2=30

30X100=300

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A function is created to represent amount of money spent on lunch if you spent five dollars a day. What restrictions would be ma

sergejj [24]

D. the range would include all real numbers.

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2 years ago

Danny earns a monthly allowance of twenty dollars and extra seventy five cents every time he is nice to his mom. Avery earns a m

Lerok [7]

Answer:

Danny: y-=.75x+20

Avery: y=1.25x+18

Step-by-step explanation:

To write a system of equations, it usually equals y=mx+b. Since Danny and Avery both earn the set monthly allowance of 20 and 18 dollars respectively, those numbers go on the variable b since it's a set amount and they start off with that amount of money if they weren't nice to their mom at all.

Since we are trying to find the overall amount of money, let y=total money a child earns every month and x=how many times the child is nice to their mother.

The extra .75 cents Danny earns go under the variable m because it is dependent on how many times he is nice to his mom. Along with Avery.

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2 years ago

Whoever is willing to help me out please do so. I will give points and brainliest. I have a headache so yeah..

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7 0

2 years ago

Read 2 more answers

What is the product 4n/4n-4 n-1/n+1

olga_2 [115]

4n/4n-4 × n-1/n+1
= 4n(n-1)/(4n-4)(n+1)
= (4n^2 - 4n)/(4n^2 + 4n - 4n-4)
= (4n^2 - 4n)/(4n^2 - 4)
= 4(n^2 - n)/4(n^2 - 1)
=(n^2 - n)/(n^2 - 1)

5 0

3 years ago

A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters

In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

$\Rightarrow y=\sqrt{x^2+100}$

Differentiating with respect to t

$\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}$

$\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}$

Since the car driving towards the intersection at 13 m/s.

so, $\frac{dx}{dt}=-13$

$\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)$

Now

$\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)$

$=\frac{24\times (-13)}{\sqrt{676}}$

$=\frac{24\times (-13)}{26}$

= -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

8 0

2 years ago