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blondinia [14]
2 years ago
9

Find the number of positive three-digit even integers whose digits are among 9, 8, 7, 5, 3, and 1.

Mathematics
2 answers:
sp2606 [1]2 years ago
7 0

Answer:

5,3,1

Step-by-step explanation:

vovikov84 [41]2 years ago
3 0

Answer:

36

Step-by-step explanation:

I know I'm late, but this is the answer.

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in a 3-digit number, the hunderds digit is one more than the ones digit and the tens digit is twice the hundreds digit. If the s
Stels [109]

Answer:362

Step-by-step explanation:

So, the ones digit is 2. Since the hundreds digit is one more, it's 3. And because the tens is twice the hundreds, it's 6. The number is 362

5 0
3 years ago
hot dog buns are sold in packages of 8 and 12. taro bought 192 total buns for a party. This is represented by the function 8x +
Lelu [443]
Here is the graphical representation of the function you provide.

You can see the the points in which the line intersects each axis.

Every point in the line is a possible option for which hot dog package was bought.

For example, Taro might have bought 0 of the packages of 8, and 16 packages of 12.

or He might've bought zero packages of 12, and 24 packages of 8.

6 0
3 years ago
Anjali paid $8 for a salad. She now has<br> $37. With how much money did she start?
sleet_krkn [62]

Answer:

Below.

Step-by-step explanation:

37+8= 45

45-8=37

so 45.

8 0
3 years ago
Read 2 more answers
In studying the insurance preferences of homeowners the following conclusions are made: A homeowner is three times as likely to
Ede4ka [16]

Answer:

0.632

Step-by-step explanation:

Given that a homeowner is three times as likely to purchase additional jewelry coverage as additional electronics coverage

If probability of purchasing additional electronics coverage = p, then prob of purchasing jewelry coverage = 3p

The two events are independent hence joint probability is product of these two.

i.e. P(both) = p(3p) =3p^2

This is given as 0.2

3p^2 =0.2\\p = 0.258

the probability that a homeowner purchases exactly one coverage.

=P(AUB)-P(A \bigcap B)

= Prob he purchases I + prob he purchases II-2(prob he purchases both)

= 0.258+3(0.258)-2(0.2)\\=0.632

5 0
3 years ago
Help me pls I would really appreciate it
Paul [167]
The first the last and the 2nd last
4 0
3 years ago
Read 2 more answers
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