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Savatey [412]
3 years ago
14

The equation of a parabola is y=x2+6x+9. Write the equation in vertex form.

Mathematics
1 answer:
nignag [31]3 years ago
6 0

Answer:

Step-by-step explanation:

Vertex form is accomplished by completing the square on the quadratic. Do this by first setting the parabola equal to 0 then moving the constant over to the other side:

x^2+6x=-9

Now take half the linear term, square it, and add it to both sides. Our linear term is 6. Half of 6 is 3, and 3 squared is 9:

x^2+6x+9=-9+9

The reason we do this is to create a perfect square binomial on the left:

(x+3)^2=0 (obviously the 0 results from the addition of 9 and -9). Move the 0 back over to the other side and set the quadratic back equal to y:

(x+3)^2+0=y

This gives you a vertex of (-3, 0), which is a minimum value, since the parabola opens upwards.

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kkurt [141]

Step-by-step explanation:

It came from nowhere.  It makes no sense to add up the balance numbers.  To illustrate, let's use a different example:

\left[\begin{array}{cc}Spend&Balance\\100&400\\100&300\\100&200\\100&100\\100&0\end{array}\right]

Adding up the money you spent, and you get $500.  Add up the balances, and you get $1000.  But why would you add the balances?  The 300 in the second line is included in the 400 in the first line.  You can't add them together.  You'd be counting the 300 twice.

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4. 110 in. = _<br>ft_<br>in.​
aliina [53]

Answer:

110 in. = 9  1/6 ft, or 9 ft 2 in

Step-by-step explanation:

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When do u evaluate exponents in the order of operations?? <br> Pls help I got 9 minutes to do this
wlad13 [49]

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Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
In triangle △ABC, ∠ABC=90°, BH is an altitude. Find the missing lengths. AB=4 and BC=3, Find AH, CH and BH.
IRISSAK [1]

Answer:

  • AH = 3.2
  • CH = 1.8
  • BH = 2.4

Step-by-step explanation:  

It can be convenient to compute the length of the hypotenuse of this triangle (AC). The Pythagorean theorem tells you ...

   AC^2 = AB^2 + CB^2

   AC^2 = 4^2 + 3^2 = 16 + 9 = 25

   AC = √25 = 5  

The altitude divides ∆ABC into similar triangles ∆AHB and ∆BHC. The scale factor for ∆AHB is ...

  scale factor ∆ABC to ∆AHB = AB/AC = 4/5 = 0.8  

And the scale factor to ∆BHC is ...  

  scale factor ∆ABC to ∆BHC = BC/AC = 3/5 = 0.6  

Then the side AH is 0.8·AB = 0.8·4 = 3.2

And the side CH is 0.6·BC = 0.6·3 = 1.8  

These two side lengths should add to the length AC = 5, and they do.  

The remaining side BH can be found from either scale factor:    

  BH = AB·0.6 = BC·0.8 = 4·0.6 = 3·0.8 = 2.4

_____  

The sides of interest are ...  

  AH = 3.2

  CH = 1.8

  BH = 2.4

3 0
3 years ago
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