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vlabodo [156]
3 years ago
10

A line passes through the points (-1,10) and (3,2). Which shows the graph of this line

Mathematics
1 answer:
crimeas [40]3 years ago
7 0

Answer:

there arent any choices-

Step-by-step explanation:

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Sergio039 [100]
50p-40p+25-p
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Find the distance between -6 - 8
Viefleur [7K]

Answer:

2

Number line.

We start at -6 or -8.

If we start from -6, we will be going __ spaces to the left until we get to -8.

Or start from -8 and go __ spaces to the right until you get to -6.

Then count the spaces.

You'll get 2.

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The length of a rectangle is given by the function l(x)=2x+1, and the width of the rectangle is given by the function w(x)=x+4.
Harlamova29_29 [7]

Answer:

a(x)=2x^2+9x+4

Step-by-step explanation:

We have been given the length and width, as well as the formula to find the area:

Length: 2x + 1

Width: x + 4

A = l * w

A = (2x + 1)(x + 4)

2x^2 + 8x + x + 4

We can add like terms now:

2x^2 + 9x + 4

Our area is 2x^2 + 9x + 4

Our answer would be a(x)=2x^2+9x+4

7 0
3 years ago
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What is the equation of the circle with center (4, 4) that passes through the point (10, 14)? HELP MEEEEE PLEASE
Gemiola [76]

Answer:

The equation of the circle can be written as:

  • \left(x-4\right)^2+\left(y-4\right)^2=136

Step-by-step explanation:

The general equation of a circle with center (h,k) and radius r is:

\left(x-h\right)^2+\left(y-k\right)^2=r^2

In our example, we know \left(h,k\right)=\left(4,4\right), as we just have to make sure we need determine \:r^2.

\left(x-4\right)^2+\left(y-4\right)^2=r^2\:\:

As the circle passes through (10, 14), that pair of values for x and y must satisfy the equation. So we have:

\left(10-4\right)^2+\left(14-4\right)^2=r^2

\mathrm{Switch\:sides}

r^2=\left(10-4\right)^2+\left(14-4\right)^2

r^2=6^2+10^2

r^2=36+100

r^2=136

Thus the equation of the circle can be written as:

\left(x-4\right)^2+\left(y-4\right)^2=136

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3 years ago
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Please explain your answer step by step thankyou
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