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3 years ago

7

What is the slope of the line on the graph? WILL GIVE BRAINLIEST

2 answers:

inessss [21]3 years ago

7 0

To find slope, you must find two points and use rise over run.
I'll use (0, -1) and (1, 5)
5 - (-1) $\frac{5-(-1)}{1-0}$ = 6
m= 6
So the slope is 6

Brainliest please!

Kobotan [32]3 years ago

5 0

Hello!!

We can look at the points given on the graph. (-1, -7), (0, -1), and (1, 5).

Now, we can the formula, where m stands for slope: m = (y2 - y1)/(x2 - x1). NOTE: (the 1's and 2's are supposed to be subscripts.

Pick two of the three given points, I'll use (0, -1) and (1, 5).

m = (5 - (-1))/(1 - 0) = 6/1 = 6

The slope of the line on the graph is 6.

Hope this helps!! Let me know if you have ANY questions.

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Find the values<br>using<br>expansion formula<br>1) 1.5×2.5

PolarNik [594]

Answer:

$3.75$

Step-by-step explanation:

$1.5 \times2. 5 \\ = 3.75$

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2 years ago

The slope of a line is 7/10 . One point on the line has coordinates (1, 2). Which ordered pair represents another point on the l

mash [69]

(x,y)

y=mx+b
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2 years ago

What is the median of 1.6 , 2.3 , 1.4 , 2.5 , 1.7

lisov135 [29]

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2 years ago

What is 3/4 as a decimal

FromTheMoon [43]

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1 year ago

Read 5 more answers

If A, B, and C are integers between 1 and 10 (inclusive), how many different combinations of A, B, and C exist such that A

Marianna [84]

$\fontsize{18}{10}{\textup{\textbf{The number of different combinations is 120.}}}$

Step-by-step explanation:

A, B and C are integers between 1 and 10 such that A<B<C.

The value of A can be minimum 1 and maximum 8.

If A = 1, B = 2, then C can be one of 3, 4, 5, 6, 7, 8, 9, 10 (8 options).

If A = 1, B = 3, then C has 7 options (4, 5, 6, 7, 8, 9, 10).

If A = 1, B = 4, then C has 6 options (5, 6, 7, 8, 9, 10).

If A = 1, B = 5, then C has 5 options (6, 7, 8, 10).

If A = 1, B = 6, then C has 4 options (7, 8, 9, 10).

If A = 1, B = 7, then C has 3 options (8, 9, 10).

If A = 1, B = 8, then C has 2 options (9, 10).

If A = 1, B = 9, then C has 1 option (10).

So, if A = 1, then the number of combinations is

$n_1=1+2+3+4+5+6+7+8=\dfrac{8(8+1)}{2}=36.$

Similarly, if A = 2, then the number of combinations is

$n_2=1+2+3+4+5+6+7=\dfrac{7(7+1)}{2}=28.$

If A = 3, then the number of combinations is

$n_3=1+2+3+4+5+6=\dfrac{6(6+1)}{2}=21.$

If A = 4, then the number of combinations is

$n_4=1+2+3+4+5=\dfrac{5(5+1)}{2}=15.$

If A = 5, then the number of combinations is

$n_5=1+2+3+4=\dfrac{4(4+1)}{2}=10.$

If A = 6, then the number of combinations is

$n_6=1+2+3=\dfrac{3(3+1)}{2}=6.$

If A = 7, then the number of combinations is

$n_7=1+2=\dfrac{2(2+1)}{2}=3.$

If A = 3, then the number of combinations is

$n_8=1.$

Therefore, the total number of combinations is

$n\\\\=n_1+n_2+n_3+n_4+n_5+n_6+n_7+n_8\\\\=36+28+21+15+10+6+3+1\\\\=120.$

Thus, the required number of different combinations is 120.

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Link : https://brainly.in/question/4909567.

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3 years ago