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Ostrovityanka [42]
3 years ago
11

A rectangular athletic field is three times as long as it is wide. If the perimeter of tje athletic field is 128 yards, what are

the dimensions
Mathematics
1 answer:
Dahasolnce [82]3 years ago
4 0
The length of the field is 48 yard while the width of the field is 16 yards.

My Work/Reasoning:
Say that the width is "x" yards. x
The length of the field is three times longer than the width. 3x
The perimeter of the rectangle is 128 yards. 128
To get the perimeter of a rectangle you multiply the sum of the length and the width by two. 2(x+3x)=128
Then you follow order of operations and add x and 3x. 2*4x=128
Then you multiply. 8x=128
After that, you divide 8 on both sides to get the width (total) in yards. x=32
Then you divide that to get the width. 32/2=16
Finally, to get the length of the field, you multiply the width of the field by three to get its length. 16*3=48
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How can you write the expression with rationalized denominator? sqrt3 - sqrt6 / sqrt 3 + sqrt 6
harina [27]
Answer:  2√2 - 3

Explanation:


The expession written properly is:

\frac{ \sqrt{3}- \sqrt{6}  }{ \sqrt{3}+ \sqrt{6} }

To rationalize that kind of expressions, this is to eliminate the radicals on the denominator you use conjugate rationalization.

That is, you have to multiply both numerator and denominator times the conjugate of the denominator.

The conjugate of √3+√6 is √3 - √6, so let's do it:

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To help you with the solution of that expression, I will show each part.

1) Numerator: (√3 - √6) . (√3 - √6) = (√3 - √6)^2 = (√3)^2 - 2√3√6 + (√6)^2 =

= 3 - 2√18 + 6 = 9 - 6√2.

2) Denominator: (√3 + √6).(√3 - √6) = (√3)^2 - (√6)^2 = 3 - 6 = - 3

3) Then the resulting expression is:

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-----------
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faltersainse [42]

Answer:

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Step-by-step explanation: See Annex

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(x/2)² = 2*x

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Now with the help of geogebra we have: In the annex segment ABCD is dy then

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V = π * [(4/3)y³ - (1/20)y⁵] |₀⁴

V =  π * [ (4/3)*4³ - 0 - 1/20)*1024 + 0 )

V = π * [256/3  - 51,20]

V = 34,13*π   cubic units

3 0
2 years ago
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