Ask question

Ask question

All categories

2 years ago

15

PLEASE HELP!!!

1 answer:

krok68 [10]2 years ago

7 0

A parabola, a graph of a quadratic function, cannot have a maximum vertex and a minimum vertex at the same time because of the shape of the graph. A parabola is a u-shaped graph. The vertex of the parabola is the point where the u changes direction; if it was increasing, it starts to decrease, and if it was decreasing, it starts to increase. Since a parabola only changes direction once, there will either be a minimum or a maximum, not both.

You might be interested in

Jonus watches the second hand on an analog clock as it moves past the numbers. What is the

slega [8]

Answer:1/12 or 8.3

Step-by-step explanation:

5 0

2 years ago

Giving Brainliestttttttt to first answer that’s correct!

Luba_88 [7]

Answer:

I think C sorry if wrong

7 0

2 years ago

Tom took 10 notecards and arranged them in piles of How many piles did Tom make?

mezya [45]

Answer:

If there in piles of 2 you have 2 piles

Step-by-step explanation:

6 0

2 years ago

What type of word a relationship does this analogy show

Trava [24]

Answer:

part/whole

Step-by-step explanation:

jazz is only a part of music, music is the whole thing and also lave tube would be a part of a bigger thing which is the cave

7 0

2 years ago

Read 2 more answers

Use synthetic substitution to evaluate the polynomial P(x) = x^3-3x^2+4x-7 for x=3

Zina [86]

Answer:

$\frac{x^3-3x^2+4x-7}{x-3} =(x^2+4)+\frac{5}{x-3}$

Step-by-step explanation:

We are given polynomial as

$P(x)=x^3-3x^2+4x-7$

and it is divided by x=3 or x-3

we can use synthetic division

so, we got

Remainder =5

Quotient is

$=x^2+0x+4$

$=x^2+4$

we can write as

$\frac{x^3-3x^2+4x-7}{x-3} =(x^2+4)+\frac{5}{x-3}$

3 0

2 years ago