Answer:
A and F
Step-by-step explanation:
first figure out the slope.
4-(-5)/2-(-3)= 9/5
slope: 9/5
y-y1=m(x-x1)
you substitute either coordinate for the second variables. we automatically take out any slopes that have a negative because the slope is positive.
C, D, E all have negative slopes so it is wrong.
B does not work because a negative times a negative is a positive. the equation shows it to be negative so it is wrong.
A & F fit the solution.
Answer:
d
Step-by-step explanation:
Answer:
cos x ≠ 0 ⇔ x ≠ 
; k ∈ N
<=> cos²x + sin²x = 1
⇔ 1 = 1
=> x = { R \ (pi/2 + k.pi); k ∈ N}
Step-by-step explanation:
<span>12.3
Volume function: v(x) = ((18-x)(x-1)^2)/(4pi)
Since the perimeter of the piece of sheet metal is 36, the height of the tube created will be 36/2 - x = 18-x.
The volume of the tube will be the area of the cross section multiplied by the height. The area of the cross section will be pi r^2 and r will be (x-1)/(2pi). So the volume of the tube is
v(x) = (18-x)pi((x-1)/(2pi))^2
v(x) = (18-x)pi((x-1)^2/(4pi^2))
v(x) = ((18-x)(x-1)^2)/(4pi)
The maximum volume will happen when the value of the first derivative is zero. So calculate the first derivative:
v'(x) = (x-1)(3x - 37) / (4pi)
Convert to quadratic equation.
(3x^2 - 40x + 37)/(4pi) = 0
3/(4pi)x^2 - (10/pi)x + 37/(4pi) = 0
Now calculate the roots using the quadratic formula with a = 3/(4pi), b = -10/pi, and c = 37/(4pi)
The roots occur at x = 1 and x = 12 1/3. There are the points where the slope of the volume equation is zero. The root of 1 happens just as the volume of the tube is 0. So the root of 12 1/3 is the value you want where the volume of the tube is maximized. So the answer to the nearest tenth is 12.3</span>
A negative times a negative is a positive, and a negative times a positive is equal to a negative. I’ve never used that program so if that what u need help with sorryyy
