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LiRa [457]
3 years ago
12

Match the theorems and terms to their definitions

Mathematics
1 answer:
Nady [450]3 years ago
6 0

Answer:

In order they are H, B, E, C, A, J, G,  F, D,  I

Step-by-step explanation:

Note that a zero of a function is the sam as a root of a function (I and J)


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A conical tank (with vertex down) is 12 feet across the top and 18 feet deep. If water is flowing into the tank at a rate of 18
Rufina [12.5K]

Answer:

qqqqqqq

Step-by-step explanation:

7 0
3 years ago
Three times the sum of a number and seven is negative thirty-six. What is the number?
Katarina [22]

Answer:

n =-19

Step-by-step explanation:

3* (n+7) = -36

Distribute

3n+21 = -36

Subtract 21 from each side

3n+21-21 = -36-21

3n = -57

Divide by 3

3n/3 = -57/3

n =-19

7 0
3 years ago
Read 2 more answers
2) two florist purchased flower bouquets and vases at the same store. The first florist bought 2 flower bouquets and two vases f
Feliz [49]
Let
b---------> <span>the cost of one flower bouquet
</span>v-------->  <span>the cost of one vase.

we know that
2b+2v=12.50-----> </span>Multiplied by -1------------->-2b-2v=-12.50
8b+2v=29---------------------------------------------> 8b+2v=29
           I add the two equations                    ------------------------
                                                                        6b=16.50
b=2.75
2*2.75+2*v=12.50---------------> v=(12.50-5.5)/2---------> v=3.5

the answer is
the cost of one flower bouquet is $2.75
the cost of one vase is $3.5

7 0
3 years ago
Prove 2√(x) + 1/√(x + 1) &lt;= 2√(x+1) for all x in [0,inf)
EleoNora [17]
Start by multiplying each side of the inequality by \sqrt{x + 1} and simplifying:

2 \sqrt x + \frac{1}{\sqrt{x+1}}  \leq  2 \sqrt{x + 1}
(2 \sqrt x + \frac{1}{\sqrt{x+1}})(\sqrt{x + 1}) \leq (2 \sqrt{x + 1})(\sqrt{x + 1})
2 \sqrt{x(x + 1)} + 1 \leq 2(x + 1)
2 \sqrt{x^2 + x} + 1 \leq 2x + 2
2 \sqrt{x^2 + x} \leq 2x + 1
\sqrt{x^2 + x} \leq x + \frac{1}{2}

From here, we can square both sides to get

x^2 + x \leq (x + \frac{1}{2})^2
x^2 + x \leq x^2 + x + \frac{1}{4}
0  \leq \frac{1}{4}, which is always true.
3 0
3 years ago
What is the factorization of the expression below?
mestny [16]

Answer:

Answer B is correct

(6x + 5)(6x - 5)

Step-by-step explanation:

36 {x}^{2}  - 25 \\  {6}^{2} {x}^{2}   -  {5}^{2}  \\  = (6x - 5)(6x + 5)

6 0
3 years ago
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