This is a cube root, so we look for factors of 162 which are perfect cubes.
Find the prime factors of 162:-
162 = 2 * 3 * 3 * 3* 3
27 = 3^3 is a perfect cube
162 = 6 * 27
so ^3√ 162 = ^3√6 * ^3√27 = ^3√6 * 3
so the simplest form is 3 ^3√6
Answer:
d, e
Step-by-step explanation:
The applicable rules of exponents are ...
(a^b)(a^c) = a^(b+c)
a^-b = 1/a^b
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In this case, it means the product is ...
(6^1)(6^0)(6^-3) = 6^(1+0-3) = 6^-2 = 1/6^2 = 1/36
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The 6 without an exponent is equivalent to 6^1, an exponent of 1.
The sum of the exponents is -2.
Add the exponents to simplify the expression.
The value of the expression is 1/36.
An equivalent is any expression that results in 6^-2. One such is (6^5)(6^-7).
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Only the last two choices, d and e, apply.
Answer:
x = -9, -2, and 3.
just set everything possible to 0.
since 0 = 0 it must be true.
Answer:
Triangle
Step-by-step explanation:
The triangle has the formula that have b*h/1/2.
Answer: C
Step-by-step explanation:
