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yulyashka [42]
3 years ago
6

Which formula can be used to find the nth term of a geometric sequence where the fifth term isn1/16 and the common ratio is 1/4?

Mathematics
1 answer:
kati45 [8]3 years ago
7 0

1/16=a(1/4)^(5-1)

1/16=a(1/4)^4

1/16=a/256

256/16=a

16=a

So the initial term is 16 so our formula is:

a(n)=16(1/4)^(n-1)

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Read 2 more answers
<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bn%5E5%7D%7Bn-6%7D%20%2A%20%5Cfrac%7Bn%5E2-6%7D%7Bn%5E8%7D" id="TexFormula1" title="\
ddd [48]

Step-by-step explanation:

Dod you mean

=  \frac{ {n}^{5} }{ {n}^{ - 2} }  \times  \frac{ {n}^{2 - 6} }{ {n}^{8} }

=  {n}^{5 - ( - 2)}  \times  {n}^{2 - 6 - 8}

=  {n}^{7}  \times  {n}^{ - 12}

=  {n}^{7 + ( - 12)}

=  {n}^{ - 5}  =  \frac{1}{ {n}^{5} }

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2 years ago
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3. Subtract 6 from both sides and divide by 3
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6 0
1 year ago
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