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3 years ago

#2 Find the segment length indicated. Assume that lines which appear to be tangent are tangent. *

Mathematics

1 answer:

gregori [183]3 years ago

4 0

The angle of a tangent and a radius is a right angle.

The missing length would be the hypotenuse. Use the Pythagorean theorem to solve.

X = SQRT(12^2 + 16^2)

X = SQRT(144 + 256)

x = SQRT(400)

X = 20

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Please help!

SpyIntel [72]

Number 1 is B
Number 2 is also B

3 0

4 years ago

A parking space is 20 feet long. A pickup truck is 6 yards long. How many inches longer is the parking space than the truck

masya89 [10]

1 yard = 3 feet.

Multiply the length of the truck by 3 to get total feet:

6 x 3 = 18 feet.

Subtract the length of the truck from the length of the parking space:

20 - 18 = 2 feet

1 foot = 12 inches.

Multiply 2 feet by 12:

2 x 12 = 24 inches longer.

7 0

3 years ago

4+2<-14 or – 5+98< 41

N76 [4]

Answer:

4+2<-14

6< -14 (False)

– 5+98< 41

93<41 (False)

Both statements are false.

6 0

3 years ago

Write and equation in standard form of the line shown.

KIM [24]

m=5

b=0

y=5x+0

trust me

7 0

3 years ago

Hey if you're willing to help me with this, it will be very much appreciated, thanks maties and mates.

Nastasia [14]

Answer:

Width=37in

Length=55in

Step-by-step explanation:

Let x in be the width dimension, the length dimension will be x+18 in. Area of a rectangle is calculated as A=lw. Given the area as2143 sq in, x can be calculated as:

$Area= x(18+x)\\\\=18x+x^2\\\\$

#Substitute for every x in our function to find the true value of x:

$x=37\\\\A=x^2+18x\\\\=37^2+18\times37\\\\=2035 \ in^2$ #l=37+18=55in

for x=38:

$x=38\\\\A=x^2+18x\\\\=38^2+18\times38\\\\=2128 \ in^2$ #l=38+18=56in

For x=39:

$x=39\\\\A=x^2+18x\\\\=39^2+18\times39\\\\=2223 \ in^2$ #l=39+1854in

From the calculations above, A television with a width of 37 in and length 55in has its area closest to 2143 sq in.

4 0

3 years ago