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aivan3 [116]
4 years ago
11

#2 Find the segment length indicated. Assume that lines which appear to be tangent are tangent. *

Mathematics
1 answer:
gregori [183]4 years ago
4 0

The angle of a tangent and a radius is a right angle.

The missing length would be the hypotenuse. Use the Pythagorean theorem to solve.

X = SQRT(12^2 + 16^2)

X = SQRT(144 + 256)

x = SQRT(400)

X = 20

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GuDViN [60]

Answer: it is b

Step-by-step explanation:

i took the test boys

5 0
3 years ago
What is the greatest common factor of 56 and 21
bonufazy [111]
21 factors: 1,3,7,21
56 factors: 1,2,4,7,8,14,28,56
7 is your GCF

6 0
4 years ago
Simplify x^3- + x^2 + y^2
aleksley [76]
Hello, there!


<span>This is already simplified as there are no like terms that can be combined. x^3 is different than x^2, so it can't be combined.

x^3 is different from y^2 so it can't be combined.

And finally, x^2 is different from y^2, so it can't be combined either.
</span>

I hope I helped!

Let me know if you need anything else!

~ Zoe
8 0
3 years ago
a motorist travelled 20km at an average speed 15km/h .if he made the return journey at an average speed of 30km/h .Find the aver
scZoUnD [109]

Answer:

20km/h

Step-by-step explanation:

8 0
3 years ago
A researcher believes that 12% of a simple random sample of adults will be able to identify a Toyota Scion by brand and model na
DochEvi [55]

Answer: 650

Step-by-step explanation:

When prior estimate of population proportion is known , then the formula to find the required sample size is given by :-

n=p(1-p)(\dfrac{z^*}{E})^2

, where p= population proportion

E= margin of error

z* = Critical value.

Let p be the proportion of adults able to identify a Toyota Scion by brand and model name.

As per given , we have

p = 12%= 0.12

E= 2.5%=0.025

Critical value for 95% confidence interval : z* = 1.960  [By z-table ]

Then, the required sample size = n=(0.12)(1-(0.12))(\dfrac{1.96}{0.025})^2

n=(0.1056)(78.4)^2

n=(0.1056)(6146.56)

n=649.076736\approx650

Thus , the required sample size = 650

6 0
3 years ago
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