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Flura [38]
3 years ago
15

What is the total number of arrangements for 3 green balls, 2 red balls, and 1 white ball?

Mathematics
1 answer:
klio [65]3 years ago
7 0

Answer:

6

Step-by-step explanation:

***If choosing one of each, this is the answer*** This wasn't clearly asked for in the question though

When counting the number of arrangements of multiple choices, multiply the number of choices of each item together.

(3)(2)(1) = 6

Here is them listed..

Green ball 1, red ball 1, white ball

Green ball 1, red ball 2, white ball

Green ball 2, red ball 1, white ball

Green ball 2, red ball 2, white ball

Green ball 3, red ball 1, white ball

Green ball 3, red ball 2, white ball

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A space S is defined as S = {1, 3, 5, 7, 9, 11} , and three subsets as A = {1, 3, 5} , B = {7, 9, 11} , C = {1, 3, 9, 11} . Assu
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Answer:

a) 0.5

b) 0.5

c) 0.67

d) 1

e) 0.83

f) 0.67

Step-by-step explanation:

a)

P(A)=n(A)/n(S)

n(A)=number of outcomes in event A=3

n(S)= Total number of outcome of an experiment=6

P(A)=3/6=1/2=0.5

b)

P(B)=n(B)/n(S)

n(B)=number of outcomes in event B=3

P(B)=3/6=1/2=0.5

c)

P(C)=n(C)/n(S)

n(C)=number of outcomes in event C=4

P(C)=4/6=2/3=0.67

d)

A∪B= {1,3,5} ∪ {7,9,11}={1,3,5,7,9,11}

P(A∪B)=n(A∪B)/n(S)=6/6=1

e)

A∪C={1,3,5}∪{1,3,9,11}={1,3,5,9,11}

P(A∪C)=n(A∪C)/n(S)=5/6=0.83

f)

A-C={1,3,5}-{1,3,9,11}={5}

(A-C)∪B={5}∪{7,9,11}={5,7,9,11}

P((A-C)∪B)=n((A-C)∪B)/n(S)=4/6=2/3=0.67

8 0
3 years ago
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