3 years ago

Write the equation of a line perpendicular to y=2x-5 that passes through the point (-2,5)

1 answer:

3 0

y = mx + b

The product of slopes of perpendicular lines is -1. The slope of the given line is 2, so the slope of the perpendicular line is -1/2.

y = (-1/2)x + b

Now use the given point to find b and finish from here.

-5 = (-1/2)(2) + b

b = ?

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