As we know,
So, we can infer that :
Now, let's calculate the mass of gases in each case :
<h3>Case A : Hydrogen ~</h3>
or
<h3>Case B : Helium ~ </h3>
or
<h3>Case C : Nitrogen ~ </h3>
or
So, the arrangement of masses from least to greatest is :
- (1.) Hydrogen < (2.) Helium < (3.) Nitrogen
Answer:
243 .....................
Answer:
4 2/3
Step-by-step explanation:
(m-4) (3m-2)=0
Use the zero product property to find the zeros
m-4 = 0 3m-2 =0
m =4 3m =2
m = 2/3
We want the sum of the zero's
4+ 2/3
4 2/3
Answer: x = ¹/₂ ± √⁸¹
------------
2
Step-by-step explanation:
First write out the equation
x² - x - 20
Now we now write the equation by equating to 0
x² - x - 20 = 0
We now move 20 to the other side of the equation. So
x² - x = 20,
We now add to both side of the equation square of the half the coefficient of the (x) and not (x²) which is (1) . So, the equation now becomes
x² - x + ( ¹/₂ )² = 20 + ( ¹/₂ )²
x² - ( ¹/₂ )² = 20 + ¹/₄
( x - ¹/₂ )² = 20 + ¹/₄, we now resolve the right hand side expression into fraction
( x - ¹/₂ )² = ⁸¹/₄ when the LCM is made 4
Taking the square root of both side to remove the square,we now have
x - ¹/₂ = √⁸¹/₄
x - ¹/₂ = √⁸¹/₂
Therefore,
x = ¹/₂ ± √⁸¹
-----------
2
Step-by-step explanation:
(2c+c) + 12 =78
3c + 12 = 78
78 - 12 = 66
66 ÷ 3 = 22
22 + 22 + 22 + 12 = 78
{ C = 22 }
