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2 years ago

14

Write the equation of a line perpendicular to y=2x-5 that passes through the point (-2,5)

1 answer:

yawa3891 [41]2 years ago

3 0

y = mx + b

The product of slopes of perpendicular lines is -1. The slope of the given line is 2, so the slope of the perpendicular line is -1/2.

y = (-1/2)x + b

Now use the given point to find b and finish from here.

-5 = (-1/2)(2) + b

b = ?

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2 years ago

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Nimfa-mama [501]

First of all, we can observe that

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2 years ago

Chris rents a car for a total of £375 The rental charges are £150 for the first day and £75 per day after that. For how many day

valkas [14]

Answer:

4 days in total

Step-by-step explanation:

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2 years ago

Use the null hypothesis H0 : μ = 98.6, alternative hypothesis Ha: μ < 98.6, and level of significance α = 0.05. 98 99.6 97.8

andrezito [222]

Answer:

The t-score is -1.8432

Step-by-step explanation:

We are given the following in the question:

98, 99.6, 97.8, 97.6, 98.7, 98.4, 98.9, 97.1, 99.2, 97.4, 99.1, 96.9, 98.8, 99.9, 96.8, 97, 98.7, 97.6, 98.7, 98.2

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{1964.4}{20} = 98.22$

Sum of squares of differences = 16.152

$s = \sqrt{\dfrac{16.152}{49}} = 0.922$

Population mean, μ = 98.6

Sample mean, $\bar{x}$ = 98.22

Sample size, n = 20

Sample standard deviation, s = 0.922

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 98.6\\H_A: \mu < 98.6$

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{98.22 - 98.6}{\frac{0.922}{\sqrt{20}} } = -1.8432$

The t-score is -1.8432

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2 years ago

Find the value of kk for which the constant function x(t)=kx(t)=k is a solution of the differential equation 3t3dxdt+5x−3=03t3dx

Dafna11 [192]

If $x(t)=k$ is constant, then $\dfrac{\mathrm dx}{\mathrm dt}=0$ , so you have

$5k-3=0\implies k=\dfrac35$

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3 years ago