26
Hope this was helpful !
<span>
Let's analyze Hannah's work, step-by-step, to see if she made any mistakes. </span>In Step 1, Hannah wrote
![\dfrac{d}{dx} (-3+8x)](https://tex.z-dn.net/?f=%20%5Cdfrac%7Bd%7D%7Bdx%7D%20%28-3%2B8x%29)
<span> as the sum of two separate derivatives </span>
![\dfrac{d}{dx}(-3)+ \dfrac{d}{dx} (8x)](https://tex.z-dn.net/?f=%20%5Cdfrac%7Bd%7D%7Bdx%7D%28-3%29%2B%20%5Cdfrac%7Bd%7D%7Bdx%7D%20%288x%29%20)
<span>using the </span><span>sum rule.
</span>
This step is perfectly fine. In Step 2,
![\dfrac{d}{dx}(8x)](https://tex.z-dn.net/?f=%5Cdfrac%7Bd%7D%7Bdx%7D%288x%29)
was kept as it is, and
![\dfrac{d}{dx}(-3)](https://tex.z-dn.net/?f=%20%5Cdfrac%7Bd%7D%7Bdx%7D%28-3%29%20)
was rewritten as
![0](https://tex.z-dn.net/?f=0)
using the constant rule.Indeed, according to the constant rule, the derivative of a constant number is equal to zero.
This step is perfectly fine. In Step 3,
![\dfrac{d}{dx} (8x)](https://tex.z-dn.net/?f=%20%5Cdfrac%7Bd%7D%7Bdx%7D%20%288x%29%20)
was rewritten as
![\dfrac{d}{dx}(8) \dfrac{d}{dx}(x)](https://tex.z-dn.net/?f=%20%5Cdfrac%7Bd%7D%7Bdx%7D%288%29%20%5Cdfrac%7Bd%7D%7Bdx%7D%28x%29%20%20)
supposedly using the constant multiple rule.
The problem is that according to the constant multiple rule,
![\dfrac{d}{dx}(8x) ](https://tex.z-dn.net/?f=%20%5Cdfrac%7Bd%7D%7Bdx%7D%288x%29%0A)
should be rewritten as
![8 \dfrac{d}{dx}(x)](https://tex.z-dn.net/?f=8%20%5Cdfrac%7Bd%7D%7Bdx%7D%28x%29%20)
and not as
![\dfrac{d}{dx}(8)\dfrac{d}{dx}(x)](https://tex.z-dn.net/?f=%5Cdfrac%7Bd%7D%7Bdx%7D%288%29%5Cdfrac%7Bd%7D%7Bdx%7D%28x%29)
.
<span>
Therefore, Hannah made a mistake in this step.</span>
Answer:
Please find attached pdf
Step-by-step explanation:
Answer:
im sorry cant help
Step-by-step explanation: