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ioda
3 years ago
5

What is the next term in the pattern? 1,-1,2,-2,3...

Mathematics
2 answers:
Digiron [165]3 years ago
7 0

Answer:

Step-by-step explanation: the pattern is going positive to negative and going further away from zero so the next term would be -3

Lesechka [4]3 years ago
4 0
Hey there!

Since, the pattern is going positive then negative repeating then it might repeat itself

1(Positive)

-1 (Negative)



2(Positive)

-2(Negative)



3(Positive)

What comes next?

The answer is mostly going to be a negative number...

Thus, your answer would most likely be:

-3

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)
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k0ka [10]

Answer:

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3 0
2 years ago
A 1/17th scale model of a new hybrid car is tested in a wind tunnel at the same Reynolds number as that of the full-scale protot
Olegator [25]

Answer:

The ratio of the drag coefficients \dfrac{F_m}{F_p} is approximately 0.0002

Step-by-step explanation:

The given Reynolds number of the model = The Reynolds number of the prototype

The drag coefficient of the model, c_{m} = The drag coefficient of the prototype, c_{p}

The medium of the test for the model, \rho_m = The medium of the test for the prototype, \rho_p

The drag force is given as follows;

F_D = C_D \times A \times  \dfrac{\rho \cdot V^2}{2}

We have;

L_p = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2 \times L_m

Therefore;

\dfrac{L_p}{L_m}  = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2

\dfrac{L_p}{L_m}  =\dfrac{17}{1}

\therefore \dfrac{L_p}{L_m}  = \dfrac{17}{1} =\dfrac{\rho _p}{\rho _p} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_p} \right)^2 = \left(\dfrac{V_p}{V_m} \right)^2

\dfrac{17}{1} = \left(\dfrac{V_p}{V_m} \right)^2

\dfrac{F_p}{F_m}  = \dfrac{c_p \times A_p \times  \dfrac{\rho_p \cdot V_p^2}{2}}{c_m \times A_m \times  \dfrac{\rho_m \cdot V_m^2}{2}} = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}

\dfrac{A_m}{A_p} = \left( \dfrac{1}{17} \right)^2

\dfrac{F_p}{F_m}  = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}= \left (\dfrac{17}{1} \right)^2 \times \left( \left\dfrac{17}{1} \right) = 17^3

\dfrac{F_m}{F_p}  = \left( \left\dfrac{1}{17} \right)^3= (1/17)^3 ≈ 0.0002

The ratio of the drag coefficients \dfrac{F_m}{F_p} ≈ 0.0002.

5 0
3 years ago
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nika2105 [10]
I’m so confused?? what’s the question?
5 0
2 years ago
Read 2 more answers
A group of dental researchers are testing the effects of acidic drinks on dental crowns. They have five containers of crowns lab
mestny [16]

Answer:

\begin{array}{cccccc}{x} & {V} & {W} & {X} & {Y} & {Z} & P(x) & {0.20} & {0.20} & {0.20} & {0.20} & {0.20} \ \end{array}

Step-by-step explanation:

Given

S = \{V,W,X,Y,Z\}

n(S) = 5

Required

The probability model

To do this, we simply calculate the probability of each container.

So, we have:

P(V) = \frac{n(V)}{n(S)} = \frac{1}{5} = 0.20

P(W) = \frac{n(W)}{n(S)} = \frac{1}{5} = 0.20

P(X) = \frac{n(X)}{n(S)} = \frac{1}{5} = 0.20

P(Y) = \frac{n(Y)}{n(S)} = \frac{1}{5} = 0.20

P(Z) = \frac{n(Z)}{n(S)} = \frac{1}{5} = 0.20

So, the probability model is:

\begin{array}{cccccc}{x} & {V} & {W} & {X} & {Y} & {Z} & P(x) & {0.20} & {0.20} & {0.20} & {0.20} & {0.20} \ \end{array}

5 0
2 years ago
the highest of three cylinders are 3 cm 9 cm and 5 cm if the cylinder has a capacity of 725 calculate the capacitance of the oth
Allushta [10]

The capacitance of the other cylinders are 2174. 94cm³ and 1208. 30cm³.

<h3>How to find the capacitance</h3>

Capacity of a cylinder is seen as its volume

Volume of a cylinder = πr²h

The heights of the cylinders are

a. 3cm

b. 9cm

c. 5cm

Let's find the radius

Capacity = 3. 142 × r² × 3

725 = 3. 142 × r² × 3

r² = \frac{725}{3. 142 * 3}

r² = \frac{725}{9. 426}

r² = 76. 91

r = √76. 91

r = 8. 77cm

Radius of the cylinders = 8. 77cm

For cylinder with height of 9cm

Capacitance = πr²h

Capacitance = 3. 142 × 8. 77 × 8. 77 × 9

Capacitance = 2174. 94 cm³

For cylinder with height of 5cm

Capacitance = 3. 142 × 8. 77 × 8. 77 × 5

Capacitance = 1208. 30 cm³

Thus, the capacitance of the other cylinders are 2174. 94cm³ and 1208. 30cm³.

Learn more about volume of a cylinder here:

brainly.com/question/9554871

#SPJ1

6 0
2 years ago
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