Answer: the number of minutes of long distance call that one can make is lesser than or equal to 12 minutes.
Step-by-step explanation:
Let x represent the number of minutes of long distance call that one makes.
The first three minutes of a call cost $2.10. After that, each additional minute or portion of a minute of that call cost $0.45. This means that if x minutes of long distance call is made, the total cost would be
2.10 + 0.45(x - 3)
Therefore, the inequality to find the number of minutes one can call long distance for $6.15 is expressed as
2.10 + 0.45(x - 3) ≤ 6.15
2.10 + 0.45x - 1.35 ≤ 6.15
0.75 + 0.45x ≤ 6.15
0.45x ≤ 6.15 - 0.75
0.45x ≤ 5.4
x ≤ 5.4/0.45
x ≤ 12
Let's simplify step-by-step To understand :)
3x2−7x−(x2+3x−9)
Distribute the Negative Sign:
=3x2−7x+−1(x2+3x−9)
=3x2+−7x+−1x2+−1(3x)+(−1)(−9)
=3x2+−7x+−x2+−3x+9
Combine Like Terms:)
=3x2+−7x+−x2+−3x+9
=(3x2+−x2)+(−7x+−3x)+(9)
=2x2+−10x+9
Answer :)
=2x2−10x+9
HOPE THIS HELPS
Hello! I can help you! In general, the larger the size, the larger the cost. We will assume that $8 is the youth size and $12 is the adult size. x is the youth side and y is the adult side. The first part of the equation is 8x + 12y, BUT the key words in the problem are AT MOST, so out sign will be less than or equal to (≤), because the number can't be higher than 216, but it could be right at that number or less, so the equation is 8x + 12y ≤ 216. The answer is A.
Answer:
$1000
Step-by-step explanation:
We can form an equation for Clayton's account: C = 500 + 10x
We can form an equation for Clayton's account: J = 400 +12x
(where x is the number of days)
When the two accounts will contain the same amount, it means: C = J
<=> 500 + 10x = 400 +12x
<=> x =50
After 50 days, there accounts will be balance. Then, we substitue x into any of the 2 equation to find out the amount: 500 + 10(50) = $1000
I^2 = -1
so,
-99 = -1*99 = i^2*99 = 99i^2
