Bradley's shoe length is 17 cm long. Which list shows the dinosaur skeletons that were more than 320 centimeters long?

The red blood cell counts (in millions of cells per microliter) for a population of adult males can be approximated by a norma

skad [1K]

Answer:

(a) Minimum red blood cells 5.744 million cells per micro liter

(b) Maximum red blood cells 5.068 million cells per micro liter.

Step-by-step explanation:

Z-score formula is = $\frac{x-u}{Standard deviation}$

Z-score = $\frac{x-5.5}{0.4}$

The value of z-score is 0.61 so then x will be;

x = 5.744

The minimum red blood cells count that can in top is 27% of count which is 5.744 million cells per micro liter.

Z-score = $\frac{x-5.5}{0.4}$

The value of z-score is 0.14 so then x will be;

x = 5.068

The maximum red blood cells count that can be in top is 14% of count which is 5.068 million cells per micro liter.

6 0

3 years ago

At the start of the year, 15 chameleons were introduced into a zoo. The population of chameleons is expected to grow at a rate o

bearhunter [10]

Answer:

option-B

Step-by-step explanation:

We are given

At the start of the year, 15 chameleons were introduced into a zoo

so, $P_0=15$

The population of chameleons is expected to grow at a rate of 41.42% every year

so, r=0.4142

and x represents the number of years since the chameleons were introduced into the zoo

now, we can set equation to find total population

and we get

$P(x)=P_0(1+r)^x$

now, we can plug values

$P(x)=15(1+0.4142)^x$

$P(x)=15(1.4142)^x$

Average rate of change between 2 years and 4 years:

we can use formula

$A_1=\frac{P(4)-P(2)}{4-2}$

now, we can plug values

$A_1=\frac{15(1.4142)^{4}-15(1.4142)^{2}}{4-2}$

$A_1=14.99914$

Average rate of change between 4 years and 6 years:

we can use formula

$A_2=\frac{P(6)-P(4)}{6-4}$

now, we can plug values

$A_2=\frac{15(1.4142)^{6}-15(1.4142)^{4}}{6-4}$

$A_2=29.99770$

Average rate of change between 6 years and 8 years:

we can use formula

$A_3=\frac{P(8)-P(6)}{8-6}$

now, we can plug values

$A_3=\frac{15(1.4142)^{8}-15(1.4142)^{6}}{8-6}$

$A_3=59.99425$

now, we will check each options

option-A:

we can see that

$A_3-A_2=30$

So, this is FALSE

option-B:

$A_1=\frac{1}{2}A_2$

So, this is TRUE

option-C:

This is FALSE

option-D:

we got

$A_1=\frac{1}{2}A_2$

so, this is FALSE

5 0

3 years ago

The price of a movie ticket at the theater is $7 for students. The price is higher for adults. A group of 4 students and 3 adult

Marat540 [252]

Given:

Student ticket price = $7

A group of 4 students and 3 adults paid $64 in all for movie tickets.

To find:

Each of the adult ticket cost.

Solution:

Let x be the cost of each adult ticket.

Then, cost of 3 adult tickets = 3x.

Cost of 1 student ticket = $7

Cost of 4 student ticket = $7(4)

According to the question,

$7(4)+3x=64$

$28+3x=64$

$3x=64-28$

$3x=36$

Divide both sides by 3.

$x=12$

Therefore, the cost of each adult ticket is $12.

6 0

3 years ago

Help me please I don’t know what to do someone help meeee

Hunter-Best [27]

Answer:

brainliest plz

Step-by-step explanation:

5 0

2 years ago

What are geometric proofs used for?

drek231 [11]

Answer:

Prove if certain shapes fit the criteria, and if they are congruent or not

Step-by-step explanation:

Geometric proofs prove if certain shapes are congruent, whether they are not. They can also prove if sides are equal when values are not given, if a certain shape fits certain criteria, and can prove the length of certain lines when the values are not given.

4 0

3 years ago