It is important to notice firs of all that the train with no stop acceleration and them no stop acceleration would have a faster travel between stops. given this is safe to assume that there is a period during while the train is not accelerating nor decelerating. To find the time that is speed is constant
let's assume non-stop accelerating and decelerating and the time lost (subtraction of both) is the time the train had constant speed:
assuming same time accelerating a decelerating we have that the distance is
x = voT + 1/2aT^2 (initiial speed = 0) (0.25 miles = 1320 feets)
1320 = 1/2 (8)(T/2)^2
T/2 = 18.17 seg
T = 36.34 seg
time of constant speed
T = 41 -36.34 = 4.66 seg
maximum speed
v = v0 + aT (initial speed = 0)
v = 8(18.17) (time accelerating)
v = 145.36 feets/sec
distance at full speed
x = v*t
x = 145.36*4.66 = 677.38 feets
Answer:
.60 + .40 + 3.00 = 4.00
Step-by-step explanation:
Answer:
The correct option is;
B. I only
Step-by-step explanation:
The central limit theorem states that when adequately large random samples are taken from a population that has a mean, μ, and standard deviation, σ, the distributions of the sample means of individual samples taken will be more or less (approximately) normally distributed
The central limit theorem is correct for both normal and skewed populations such that estimates can be made about the population mean based on available sample mean information.
Answer:
x=k+c over 7
Step-by-step explanation:
7x-c+c=k+c
7x=k+c
divide both sides by 7
Answer:
0.6 probability.
Step-by-step explanation:
Probability of an equally likely situation is measured by # of successes/total # of possibilities.
Thus, there are 3 different values of success(2,3,4)
On the other hand, there are 5 possible different values on the list as per the question(0,1,2,3,4).
Therefore, our probability is equal to 3/5 = 0.60 = 60%
