(0,30), (1,20)
(20-30)/(1-0) = -10/1 = -10 slope
We know y intercept is 30
Equation: y = -10x + 30
Answer:
Option A is correct
The function
has real zeroes at x =-10 and x =-6
Explanation:
Given: The real zeroes or roots are x = -10, and x = -6
To find the quadratic function of degree 2.
where α,β are real roots. ....[1]
Here, α= -10 and β= -6
Sum of the roots:
α+β = -10+(-6) = -10-6 = -16
Product of the roots:
αβ = (-10)(-6)= 60
Substitute these value in equation [1] we have;

Therefore, the quadratic function for the real roots at x =-10 and x =-6 ;

Answer:
D 5/3
Step-by-step explanation:
Secθ= Hypotenuse/Adjacent
Secθ=10/6
Simplify: 10/6 -->5/3
Ans: D 5/3
remember your six trigonometric functions:
Sinθ=Opp/Hyp -->Cscθ=Adj/Hyp
Cosθ=Adj/Hyp -->Secθ=Hyp/Adj
Tanθ=Opp/Adj-->Cotθ=Opp?Adj
It is basically the opposite of each other, don't forget when you are at the last step you simplify! never forget. Also working with square roots will be a bit tricky when converting to Csc/ Sec/ Cot. Just noting you that Square roots don't belong in denominators!
Answer:
120, 15
Step-by-step explanation: