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asambeis [7]
3 years ago
10

Taylor and Nora go to the movie theater and purchase refreshments for their friends. Taylor spends a total of $69.00 on 6 drinks

and 4 bags of popcorn Nora spends a total of $96.00 on 12 drinks and bag of popcorn. Write a system of equations that can be used to find the price of one drink and the price of one bag of popcorn. Using these equations , determine and state the price of a drink, to the nearest cent .
Mathematics
2 answers:
Ivahew [28]3 years ago
5 0

Answer:

System of equations also known as simultaneous equation is:

6x + 4y = $69

12x + y = $96

The cost of a drink using the simultaneous equation above is $7.50

Step-by-step explanation:

Let x represent the cost of a drink at the movie theater

Let y represent the cost a bag of popcorn at the movie theater

Taylor purchases 6 drinks and 4 bags of popcorn with a total of $69. Mathematically, this means:

6x + 4y = $69 .......... (eqn 1)

Nora purchases 12 drinks and 1 bag of popcorn with a total of $96. Mathematically, this means:

12x + 1y = $96 .......... (eqn 2)

Combining these two equations, we have a simultaneous equation that can be used to determine the cost of each drink and bag of popcorn. We use elimination method to solve for x and y in the equations.

We multipy (eqn 1) by 2 and (eqn 2) by 1 in order to make the x variables in both equations equal. We have

2 × 6x + 4y = $69

1 × 12x + 1y = $96

Eqn 1 and 2 becomes

12x + 8y = 138.......... (eqn 3)

12x + 1y = 96........... (eqn 4)

Next, we subtract eqn 4 from eqn 3 to have:

7y = 42

y = 6

Since y=6, we substitute the value of y into eqn 1

6x + 4y = 69

6x + 4(6) = 69

6x + 24 = 69

6x = 69 - 24

6x = 45

Divide both sides by 6

x = 7.5

The cost of one drink denoted by x is $7.5 while the cost of one bag of popcorn denoted by y is $6.

fgiga [73]3 years ago
4 0

Answer:

The system if equation that can be used to derive this are

6x + 4y = 69 AND

12x + y = 96

The price of a drink is $7.5

Step-by-step explanation:

The question here says that Taylor and Nora went to the movie theater and purchase refreshments for their friends. Taylor spends a total of $69.00 on 6 drinks and 4 bags of popcorn Nora spends a total of $96.00 on 12 drinks and bag of popcorn.And we are now told to write a system of equations that can be used to find the price of one drink and the price of one bag of popcorn. Using these equations,we should determine and state the price of a drink, to the nearest cent .

Now, Let's assume that the price of a drink is "X" and that of a bag of popcorn to be Y

The first person made a purchase which led to the equation

6x + 4y = 69______ equation 1

And the second person also made a purchase that lead to the equation

12x + y = 96_____ equation 2

We make y the subject of the formula in equation 2 and apply it in 1

Y = 96 - 12x

Now apply the above in equation 1

6x + 4y = 69

6x + 4(96 - 12x)= 69

6x + 384 - 48x = 69

42x = 384 - 69

X = 315/42

X = 7.5

Substitute x= 7.5 in equation 2

12x + y = 96

12(7.5) + y = 96

90 + y = 96

Y = 6

Therefore, the price of a drink is $7.5

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Answer:

Step-by-step explanation:

Hello!

The objective is to study whether there is a greater force after impacting on one- handed backhand drive in advanced tennis players than in intermediate tennis players.

Sample 1: Advanced tennis players

X₁: Force (N) on the hand just after impact on a one- handed backhand drive for an advanced tennis player.

n₁= 6

X[bar]₁= 40.29 N

S₁= 11.29

Sample 2: Intermediate players

X₂: Force (N) on the hand just after impact on a one- handed backhand drive for an intermediate tennis player.

n₂= 8

X[bar]₂= 21.40

S₂= 8.30

Assuming that both variables have a normal distribution and both population variances are equal, to compare these two populations is best to do so trough their population means using a t-test for independent samples.

If the force is greater for the advanced players than for the intermediate players, then you'd expect the population mean for the advanced players to be greater than the population mean for the intermediate players:

H₀: μ₁ ≤ μ₂

H₁: μ₁ > μ₂

α: 0.05

t= \frac{(X_[bar]_1-X[bar]_2)-(Mu_1-Mu_2)}{Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } } ~~t_{n_1+n_2-2}

Sa= \sqrt{\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2} } = \sqrt{\frac{5*127.51+7*68.92}{6+8-2} }= 9.66

t_{H_0}= \frac{(40.29-21.40)-0}{9.66\sqrt{\frac{1}{6} +\frac{1}{8} } } = 3.62

Using the p-value approach, the decision rule is

If p-value ≤ α, reject the null hypothesis

If p-value > α, do not reject the null hypothesis

The p-value for this test is 0.00024, it is less than the level of significance, so the decision is to reject the null hypothesis.

This means that at a 5% significance level you can conclude that the average force experienced on the hand after a one-handed backhand drive for advanced players is greater than the average force experienced on the hand after a one-handed backhand drive for intermediate players.

I hope this helps!

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