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diamong [38]
3 years ago
13

When writing a repeating decimal as a fraction does the number of repeating digits use matter

Mathematics
1 answer:
Gala2k [10]3 years ago
8 0

Answer:

see below

Step-by-step explanation:

yes it matters, if you don't know how to write a repeating decimal as a fraction you can use this trick

let's say we don't know what it is

0.33333333...

so we see that there's only one repeating digit

so the answer is

(the repeating digit)/(9)=3/9

and that simplyfies to 1/3

let's try another one

0.67676767...

as you can see know the repeating is 67

so the answer is

(the thing that repeats)/(99)=67/99

do you see a pattern?

when we have a number x of repeating decimals

the denominator of the fraction (the thing that's down) is 9999..99 in there must be x 9's

let me explain

if you have 3 repeating decimals

the denominator will be 999

you see 3 nines

and so on.

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alpha and beta are the zeros of the polynomial x^2 -(k +6)x +2(2k -1). Find the value of k if alpha + beta = 1/2 alpha beta(ITS
serious [3.7K]

Answer:

k=\frac{-11}{2}.

Step-by-step explanation:

We are given \alpha and \beta are zeros of the polynomial x^2-(k+6)x+2(2k-1).

We want to find the value of k if \alpha+\beta=\frac{1}{2}.

Lets use veita's formula.

By that formula we have the following equations:

\alpha+\beta=\frac{-(-(k+6))}{1}  (-b/a where the quadratic is ax^2+bx+c)

\alpha \cdot \beta=\frac{2(2k-1)}{1} (c/a)

Let's simplify those equations:

\alpha+\beta=k+6

\alpha \cdot \beta=4k-2

If \alpha+\beta=k+6 and \alpha+\beta=\frac{1}{2}, then k+6=\frac{1}{2}.

Let's solve this for k:

Subtract 6 on both sides:

k=\frac{1}{2}-6

Find a common denominator:

k=\frac{1}{2}-\frac{12}{2}

Simplify:

k=\frac{-11}{2}.

7 0
3 years ago
SOS NEED NOW
sashaice [31]

Answer:

Step-by-step explanation:

common difference is 6

4 0
3 years ago
The nth term of 50, 80, 110 is...
Olenka [21]

Answer:

a_n=50+(n-1)30

Step-by-step explanation:

Given series is,

50,80,110....

First term, a = 50

Common difference, d = 80-50 = 30

We need to find the nth term of the given sequence.

The nth term of an AP is given by :

a_n=a+(n-1)d

Put a = 50 and d = 30 in the above formula

a_n=50+(n-1)30

Hence, the nth term of the sequence is a_n=50+(n-1)30.

5 0
3 years ago
69632 + 69469 - 59303 ​
Gala2k [10]

Answer: 79798

Step-by-step explanation:

139101 - 59303

= 79798

please give me a brainliest answer

3 0
3 years ago
Read 2 more answers
Increase the product if w and 8 by 15
Sergeu [11.5K]

Answer:

This question is hard to understand

Step-by-step explanation:

(w+8) × 15   ???

7 0
3 years ago
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