Alright, so to simplify we would take the largest number that would go into both 16 and 32 and divide both numbers by that. Do you know what that would be?
Let
x-------> total peanuts originally from the bag
we know that
1) Phillip took 1/3 of the peanuts from the bag--------> (1/3)*x
remaining=x-(1/3)*x-------> (2/3)*x
2) Joy took 1/4 of the remaining peanuts-------> (1/4)*[(2/3)*x]----> (1/6)*x
remaining= (2/3)*x-(1/6)*x------> (1/2)*x
3) Brett took 1/2 of the remaining peanuts------> (1/2)*(1/2)*x-----> (1/4)*x
remaining= (1/2)*x-(1/4)*x-------> (1/4)*x
4) Preston took 10 peanuts------> 10
(1/4)*x-10=71----> multiply by 4 both sides----> x-40=284----> x=324 peanuts
5) Total originally peanuts from the bag is equal to 324 peanuts
6) Phillip took (1/3)*x-----> (1/3)*324=108 peanuts
7) Joy took (1/6)*x------> (1/6)*324=54 peanuts
8) Brett took (1/4)*x------> (1/4)*324=81 peanuts
9) Preston took 10
so
check
108+54+81+10=253
remaining=324-253------> remaining=71-------> is correct
SOLUTION:
Step 1:
In this question, we are given the following:
Step 2:
The details of the solution are as follows:
Step-by-step explanation:
Given :
At the state fair, admission at the gate is $9.
In addition, the cost of each ride is $3.
Suppose that Sam will go on x rides.
Then, cost of x rides ( in dollars) = Cost per ride x Number of rides
=3x
Total cost ( in dollars) : Admission fee + cost of x rides
= 9+3x
Sam wants the total number of dollars he spends on admission and rides to be at most t ( less than or equal to t )
CONCLUSION:
The final answer is:
Using the values and variables given, write an inequality describing this.
Question 1:
All provided options would give the best deal on an item
Answer: Option d [all of the above]
Question 2:
When an item's price is knocked off by 15%, it means the item has only 85% of its original value left to pay. Hence, a discount of 15% means multiplying the original price by 85%
Answer: option C
