Answer:
There are 38 premium tickets and 82 regular tickets in a pile.
Step-by-step explanation:
Given,
Total number of tickets = 120
Total amount = $5812
Solution,
Let the number of premium tickets be x.
And the number of regular tickets be y.
Total number of tickets is the sum of total number of premium tickets and total number of regular tickets.
So the equation can be written as;

Again,total amount is the sum of total number of premium tickets multiplied by cost of each premium ticket and total number of regular tickets multiplied by cost of each regular ticket.
So the equation can be written as;

Now We will multiply equation 1 by 25 we get;

Now Subtracting equation 3 from equation 2 we get;

We will now substitute the value of x in equation 1 we get;

Hence There are 38 premium tickets and 82 regular tickets in a pile.
The picture in the attached figure
Part 1) <span>
What is the total area of the swimming pool?</span>
we know that
<span>area of the swimming pool=area rectangle-area semi circle
area rectangle=20*36-----> 720 ft</span>²
area semicircle=pi*r²/2
r=18/2----> 9 ft
area semicircle=pi*9²/2----> 127.17 ft²
area of the swimming pool=720 ft²-127.17 ft²----> 592.83 ft²
the answer Part 1) isThe area of the swimming pool is 592.83 ft²Part 2) <span>What is the perimeter of the swimming pool?
</span>
perimeter of the swimming pool=perimeter of rectangle-18 ft+perimeter semi circle
perimeter of rectangle=2*[20+36]---> 112 ft
perimeter semi circle=2*pi*r/2----> pi*r
r=9 ft
perimeter semi circle=pi*9----> 28.26 ft
so
perimeter of the swimming pool=112 ft-18 ft+28.26 ft----> 122.26 ft
the answer Part 2) is122.26 ft
The answer is permutation. It is <span>the action of changing the arrangement, especially the linear order, of a set of items.
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</span>
For this case we have the following variables:
x: number of months
f (x): number of caps sold
The function that models the problem is given by:

By the time the store sells 64 caps we have:

From here, we clear the number of months:

Answer:
the store sells 64 caps in 3 monts
A. month 3
520/104=5/1=6,5/1,3=k, where k=5