Let s and g represents the numbers of suits and gowns produced.
The number of zippers used is 2s+g.
The number of buttons used is 5s+8g.
In order to use all of the available zippers and buttons, we must have ...
- 2s + g = 171
- 5s + 8g = 576
Cramer's rule tells you the solution to the system
Is given by
- x = (bf-ey)/(bd-ea)
- y = (cd-fa)/(bd-ea)
Using this rule on the equations for zippers and buttons, we have
... s = (1·576 -8·171)/(1·5 -8·2) = -792/-11 = 72
... g = (171·5 -2·576)/-11 = -297/-11 = 27
72 suits and 27 gowns can be made from available zippers and buttons.
I can’t see it , it’s to blurry dude
Answer:
Rope jumping, slow pace, < 100 skips/min, 2 foot skip, rhythm bounce 8.8 630
Rope jumping, moderate pace, 100-120 skips/min, general, 2 foot skip, plain bounce 11.8 845
Rope skipping, general 12.3 881
Rope jumping, fast pace, 120-160 skips/min 12.3 881
Step-by-step explanation:
Answer:
segment d.
Step-by-step explanation:
Here is the solution...
1) ![\sqrt[3]{135} \\](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B135%7D%20%5C%5C)
Solution
We can rewrite ![\sqrt[3]{135} = \sqrt[3]{27} *\sqrt[3]{5}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B135%7D%20%3D%20%5Csqrt%5B3%5D%7B27%7D%20%2A%5Csqrt%5B3%5D%7B5%7D)
Here, ![\sqrt[3]{27} = 3](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27%7D%20%3D%203)
Now substitute the value, we get
![\sqrt[3]{135} = 3 \sqrt[3]{5}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B135%7D%20%3D%203%20%5Csqrt%5B3%5D%7B5%7D)
The answer is ![3\sqrt[3]{5}](https://tex.z-dn.net/?f=3%5Csqrt%5B3%5D%7B5%7D)
2) ![-5\sqrt[3]{40} Solution[tex]-5\sqrt[3]{40} = -5\sqrt[3]{8} *\sqrt[3]{5}](https://tex.z-dn.net/?f=-5%5Csqrt%5B3%5D%7B40%7D%20%3C%2Fp%3E%3Cp%3E%3Cstrong%3ESolution%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3E%5Btex%5D-5%5Csqrt%5B3%5D%7B40%7D%20%3D%20-5%5Csqrt%5B3%5D%7B8%7D%20%2A%5Csqrt%5B3%5D%7B5%7D)
Here ![\sqrt[3]{8} = \sqrt[3]{2^{3} } = 2\\](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B8%7D%20%3D%20%5Csqrt%5B3%5D%7B2%5E%7B3%7D%20%7D%20%3D%202%5C%5C)
Therefore, we get ![-5*2\sqrt[3]{5} = -10 \sqrt[3]{5}](https://tex.z-dn.net/?f=-5%2A2%5Csqrt%5B3%5D%7B5%7D%20%3D%20-10%20%5Csqrt%5B3%5D%7B5%7D)
The answer is-10 \sqrt[3]{5}[/tex]
2) ![2\sqrt[3]{5} * 4\sqrt[3]{8}](https://tex.z-dn.net/?f=2%5Csqrt%5B3%5D%7B5%7D%20%2A%204%5Csqrt%5B3%5D%7B8%7D)
Solution
![\sqrt[3]{8} = 2](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B8%7D%20%3D%202)
Now plug in the above in the given expression, we get
![2\sqrt[3]{5} * 4*2 = 16\sqrt[3]{5}](https://tex.z-dn.net/?f=2%5Csqrt%5B3%5D%7B5%7D%20%2A%204%2A2%20%3D%2016%5Csqrt%5B3%5D%7B5%7D)
{2*4*2 = 16]
The answer is ![16\sqrt[3]{5}](https://tex.z-dn.net/?f=16%5Csqrt%5B3%5D%7B5%7D)
