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3 years ago

Can someone help me plz

Mathematics

2 answers:

gulaghasi [49]3 years ago

8 0

I want to help but Im lost in this one. Sorry bud....

alexandr402 [8]3 years ago

3 0

Answer:

help me first plz i will help u

Step-by-step explanation:

PLEASE HELP ME

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Find the value of x. 101 x +29

iVinArrow [24]

Answer:

x = 50

Step-by-step explanation:

101 + (x + 29) = 180

130 + x = 180

x = 180 - 130

x = 50

4 0

3 years ago

Read 2 more answers

At the local gas station gasoline costs $2.75 for per gallon and diesel costs $3.02 per gallon. Gabriel needs to purchase 15.2 g

Ainat [17]

Answer:

The total amount paid by Gabriel at the local gas station is $70.49.

Step-by-step explanation:

Cost of gasoline per gallon = $2.75

Cost of diesel per gallon = $3.02

Amount of gasoline Gabriel needs = 15.2 gallons

Amount of diesel Gabriel needs = 9.5 gallons

Compute the total amount paid by Gabriel at the local gas station as follows:

Total Cost = Cost of gasoline × Amount of gasoline

+ Cost of diesel × Amount of diesel

$=(2.75\times 15.2)+(3.02\times 9.5)\\\\=41.8+28.69\\\\=70.49$

Thus, the total amount paid by Gabriel at the local gas station is $70.49.

7 0

3 years ago

Weatherwise magazine is published in association with the American Meteorological Society. Volume 46, Number 6 has a rating syst

lisabon 2012 [21]

Answer:

a) c) μ = 16.4.

b) d) μ > 16.4.

c) a) μ < 16.4.

d) c) μ ≠ 16.4.

e) d) right; left; both.

Step-by-step explanation:

Question a:

Test if it is getting worse, so at the alternative hypothesis we test if the mean is of greater than 16.4 inches, but at the null hypothesis we test if it is still of 16.4 options, so option C.

Question b:

At the alternative hypothesis we test if the mean is of greater than 16.4 inches, as said above, so the answer is given by option d.

Question c:

Dying down, so if the mean is lower than 16.4 inches, so option a.

Question d:

Don't know, so just test if it is different, which includes both lower or greater, so the correct answer is given by option c.

Question e:

Test if more -> right, so on question b) is a right tailed test.

Test if less -> left, so on question c) is a left tailed test.

Different -> both sides, so on question d) it is a two-tailed test.

Thus the correct answer is given by option d.

3 0

3 years ago

A ship leaves port at 10 miles per hour, with a heading of N 35° W. There is a warning buoy located 5 miles directly north of th

Leno4ka [110]

The value of the angle subtended by the distance of the buoy from the

port is given by sine and cosine rule.

The bearing of the buoy from the is approximately 307.35°

Reasons:

Location from which the ship sails = Port

The speed of the ship = 10 mph

Direction of the ship = N35°W

Location of the warning buoy = 5 miles north of the port

Required: The bearing of the warning buoy from the ship after 7.5 hours.

Solution:

The distance travelled by the ship = 7.5 hours × 10 mph = 75 miles

By cosine rule, we have;

a² = b² + c² - 2·b·c·cos(A)

Where;

a = The distance between the ship and the buoy

b = The distance between the ship and the port = 75 miles

c = The distance between the buoy and the port = 5 miles

Angle ∠A = The angle between the ship and the buoy = The bearing of the ship = 35°

Which gives;

a = √(75² + 5² - 2 × 75 × 5 × cos(35°))

By sine rule, we have;

$\displaystyle \frac{a}{sin(A)} = \mathbf{ \frac{b}{sin(B)}}$

Therefore;

$\displaystyle sin(B)= \frac{b \cdot sin(A)}{a}$

Which gives;

$\displaystyle sin(B) = \mathbf{\frac{75 \cdot sin(35^{\circ})}{\sqrt{75^2 + 5^2 - 2 \times 75\times5\times cos(35^{\circ}) } }}$

$\displaystyle B = arcsin\left( \frac{75 \cdot sin(35^{\circ})}{\sqrt{75^2 + 5^2 - 2 \times 75\times5\times cos(35^{\circ}) } }\right) \approx 37.32^{\circ}$

Similarly, we can get;

$\displaystyle B = arcsin\left( \frac{75 \cdot sin(35^{\circ})}{\sqrt{75^2 + 5^2 - 2 \times 75\times5\times cos(35^{\circ}) } }\right) \approx \mathbf{ 142.68^{\circ}}$

The angle subtended by the distance of the buoy from the port, C is therefore;

C ≈ 180° - 142.68° - 35° ≈ 2.32°

By alternate interior angles, we have;

The bearing of the warning buoy as seen from the ship is therefore;

Bearing of buoy ≈ 270° + 35° + 2.32° ≈ 307.35°

Learn more about bearing in mathematics here:

brainly.com/question/23427938

5 0

2 years ago

F(t) = t-1 g(t)= t^3 + 4t Find (f -g)(t)

Annette [7]

Answer:

Step-by-step explanation:

t - 1 - t^3 - 4t

-t^3 - 3t

5 0

3 years ago