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Arlecino [84]
4 years ago
15

What is the area of the button? Use 3.14 for π and round to the nearest tenth. The circumference of a button is 40.8 millimeters

. What is the radius of the button? Use 3.14 for π and round to the nearest tenth. i need this answered quick
Mathematics
1 answer:
Vika [28.1K]4 years ago
4 0

Answer: radius = 6.5millimeters; Area = 132.7m²

Step-by-step explanation:

The circumference of a circle = 2πr

The area of a circle = πr²

The circumference of a button is 40.8 millimeters. Then we can get the radius, thus will be:

Circumference = 2πr

40.8 = 2 × 3.14 × r

40.8 = 6.28r

r = 40.8/6.28

r = 6.5

Radius is 6.5 millimeters

Area = πr²

Area = 3.14 × 6.5 × 6.5

Area = 132.7m²

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U could easily do this on Photo-math- but here: 6(x−3)
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3 years ago
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Order six and three tenths repeating, negative six and four ninths, 630%, and −6.1 from least to greatest.
NNADVOKAT [17]

The order of six and three tenths repeating, negative six and four ninths, 630%, and −6.1 from least to greatest is negative six and four ninths, −6.1, 630%, six and three tenths repeating. option D

<h3>Ascending order</h3>

This is the arrangements of numbers from the least to the greatest, that is, from lower value to higher value.

six and three tenths repeating

= 6.333

negative six and four ninths

= -6 4/9

= -6.444

630%

= 630/100

= 6.3

−6.1

From least to greatest:

  • negative six and four ninths
  • −6.1
  • 630%
  • six and three tenths repeating

Therefore, the order six and three tenths repeating, negative six and four ninths, 630%, and −6.1 from least to greatest is negative six and four ninths, −6.1, 630%, six and three tenths repeating. option D

Learn more about ascending order:

brainly.com/question/12783355

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4 0
1 year ago
Given a sample mean difference of 23, a standard error of 4.2, and a critical t value of 2.262, what are the values for the conf
erastova [34]

Answer: (13.4996, 32.5004)

Step-by-step explanation:

The confidence interval for mean difference is given by :-

(\overline{x}_1-\overline{x}_2)\pm t^*\times SE ,

where (\overline{x}_1-\overline{x}_2) = sample mean difference .

t^*= critical t value (two-tailed)

SE= Standard error.

Given : (\overline{x}_1-\overline{x}_2)=23

t^*=2.262

SE= 4.2

Now, the confidence interval for mean difference will be :-

23\pm (2.262)\times (4.2)\\\\= 23\pm9.5004\\\\=(23-9.5004,\ 23+9.5004)\\\\=(13.4996,\ 32.5004)

Hence, the required confidence interval : (13.4996, 32.5004)

8 0
3 years ago
No clue what this is either haha​
dybincka [34]

Answer:

x=27

Step-by-step explanation:

63+90+x=180

63+90=153

180-153= 27

6 0
3 years ago
X²=361/100,<br> please help<br> ​
navik [9.2K]
Answer would be 3.61.
5 0
3 years ago
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