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tia_tia [17]
3 years ago
10

Write two ratios that are equivalent to 1:1

Mathematics
1 answer:
Zolol [24]3 years ago
3 0
4:4 and 5:5 are <span> two ratios that are equivalent to 1:1</span>
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Andrew is two years older than Beatrice, and Chris is three years younger than Beatrice.
In-s [12.5K]

Answer:

Beatrice's age is 34

Step-by-step explanation:

Beatruce = B

Andrew = B+2

Chris= B-3

B+(B+2) +(B-3 )= 67-B

3B-1 = 67-B

2B -1 = 67

2B= 68

B = 34

Beatrice is 34

Andrew is 36   (34+2)

Chris is 31 (34-3)

36+31 = 67

6 0
2 years ago
James sets off from home on his bike.The graph shows his journey.A)what is James average speed on his outward journey?B)How long
katen-ka-za [31]

Answer:

a) ~10.58 km/h

b) 45 min

c) 15 km/h

Step-by-step explanation:

a) 45km for 4 hours and 15min (4.25 hours) = 45 / 45.25 ~= 10.58 km/h

b) From 4:15 to 5 = 45min

c) 45km for 3 hours (5:00 to 8:00) = 45 / 3 = 15 km/h

NOTE!

The author actually wanted the answer on A) to be 10 km/h and the journey to be 4.5 hours (4 hours 30min) but instead they made it 4.25 (as shown on the graph, since 1 square is 30 minutes).

5 0
3 years ago
Evaluate the limit 8n^2+5n+2/3+2n
Vlada [557]

Answer:

8n^2+7n+2/3

Step-by-step explanation:

combine like terms

5n+2n=7n

7 0
2 years ago
Read 2 more answers
The doctor recommended that Mike increase the number of calories he burns working out from 1,500 to 1,800. By what percent did t
Viefleur [7K]

Answer: The number of calories increased by 20%.

Step-by-step explanation:

Given : The doctor recommended that Mike increase the number of calories he burns working out from 1,500 to 1,800.

Previous number of calories he used to burn = 1,500

Increase in calories = 1800-1500=300

Now , the percent increase in calories = \dfrac{\text{Increase in calories}}{\text{previous calories}}\times100

=\dfrac{300}{1500}\times100=20\%

Hence , the number of calories increased by 20%.

3 0
3 years ago
2.2 geometry i need the answers
Strike441 [17]

Answer:

Where’s the picture

Step-by-step explanation:

8 0
3 years ago
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