The answer is the question
Number 5 should be no solution becuase the n's cancel out.
For 6:
Part A is -2 because slope represents the change in weigh/change in time (-2/1 or -2)
Part B is y=-2x+231 (-2 is the slope and 231 is the y-intercept)
For part C, based on the slope, we can find that her weight will go below 200 at week 16 when it is 199
Hope this helps!
Answer:
(sin x)^2*(sec x) is positive in QII
Step-by-step explanation:
(sin x)^2 is always 0 or positive. Here x lies in QII.
sec x is positive when the adjacent side is positive and negative when the adjacent side is negative. In QII the adjacent side is positive.
In summary, (sin x)^2*(sec x) is positive in QII
Answer:
C. x 0 1 2 p(x) 0.35 0.60 0.05
Step-by-step explanation:
50% chance of survival
Let:
x = older eaglet survive
y = younger eaglet survive
Hence,
P(x = 0) (none of the eaglet survive)
P(x = 1) (only one survive)
P(x = 2) (both survive)
P(x) = 0.5
P(x') = 1 - 0.5 = 0.5
P(x n y) = 0.5 * 0.1 = 0.05 ( both survive)
P(only one survive)
P(y n x') + p(y' n x)
(0.5 * 0.3) + (0.5 * (1 - 0.1))
0.15 + 0.45 = 0.6
P(none survives)
1 - (0.60 + 0.05)
= 0.35
X _______ 0 ______ 1 ______ 2
P(x) ____ 0.35 ____ 0.60 ___ 0.05
Neither of them are correct. When you plug in both of the fractions into the equation, you get answers like 2/9 (from plugging in 1/3) and 1/9 (from plugging in 1/6). None of them are equal to 9.
