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riadik2000 [5.3K]
3 years ago
9

Find the measure of the missing side

Mathematics
2 answers:
Thepotemich [5.8K]3 years ago
8 0

Answer:

10.3

Step-by-step explanation:

a^2 + b^2 = c^2

3.9^2 + b^2 = 11^2

b^2 = 121 - 15.21

b = 10.3

Butoxors [25]3 years ago
3 0

Answer:

10.3

Step-by-step explanation:

We use the pythagorean theorem. (a^2+b^2=c^2)

3.9^2 + b^2 = 11^2

3.9^2 = 15.21

11^2 = 121

15.21 + b^2 = 121

Subtract 15.21 from both sides

b^2=105.79

Take the square root of both sides

b = 10.28

10.28 is closest to 10.3 and it is also rounded to 10.3, therefore 10.3 is the answer.

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20,000,000 + 3,000,000 + 60,000 + 4,000 + 900 + 7 in standard form
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3 years ago
Suppose an automotive repair company wants to determine the current percentage of customers who keep up with regular vehicle mai
Nina [5.8K]

Answer: 1692

Step-by-step explanation:

Formula to find the sample size :

n=p(1-p)(\dfrac{z_{\alpha/2}}{E})^2

Given : Confidence level : (1-\alpha)=0.90

⇒ significance level =\alpha= 0.10

z-value for 90% confidence interval (using z-table)=z_{\alpha/2}=1.645

Prior estimate of the population proportion (p) of customers who keep up with regular vehicle maintenance is unknown.

Let we take p= 0.5

Margin of error : E= 2%=0.02

Now, the required sample size will be :

n=0.5(1-0.5)(\dfrac{1.645}{0.02})^2

Simplify , we get

n=(0.25)(6765.0625)=1691.265625\approx1692

Hence, the required sample size = 1692

8 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP !!!!! What would these be in scientific notation ?
Zarrin [17]

\text{the scientific notation}\\\\a\cdot10^n\ \text{where}\ 1\leq a < 10\ \text{and}\ n\in\mathbb{Z}

5\underbrace{7,909,000}_{\leftarrow7}km=5.7909\cdot10^7km\\\\1\underbrace{08,200,000}_{\leftarrow8}km=1.082\cdot10^8km\\\\1\underbrace{49,600,000}_{\leftarrow8}km=1.496\cdot10^8km\\\\2\underbrace{27,940,000}_{\leftarrow8}km=2.2794\cdot10^8km\\7\underbrace{78,330,000}_{\leftarrow8}km=7.7833\cdot10^8km\\\\1,\underbrace{424,600,000}_{\leftarrow9}km=1.4246\cdot10^9km\\\\4,\underbrace{498,252,900}_{\leftarrow9}km=4.4982529\cdot10^9km

4 0
3 years ago
A teacher teaches two classes with 8 students each. Each student has a 95% chance of passing their class independent of the othe
dsp73

Answer:

0.4466 = 44.66% probability that, in exactly one of the two classes, all 8 students pass.

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they pass, or they do not. The probability of an student passing is independent of other students, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Probability that all students pass in a class:

Class of 8 students, which means that n = 8

Each student has a 95% chance of passing their class independent of the other students, which means that p = 0.95

This probability is P(X = 8). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 8) = C_{8,8}.(0.95)^{8}.(0.05)^{0} = 0.6634

Find the probability that, in exactly one of the two classes, all 8 students pass.

Two classes means that n = 2

0.6634 probability all students pass in a class, which means that p = 0.6634.

This probability is P(X = 1). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,1}.(0.6634)^{1}.(0.3366)^{1} = 0.4466

0.4466 = 44.66% probability that, in exactly one of the two classes, all 8 students pass.

3 0
3 years ago
A field is a rectangle with a perimeter of 1260 feet. The length is 100 feet more than width. Find the width and length of the r
lyudmila [28]

To solve this problem you must apply the proccedure shown below:

1. The formula for calculate the perimeter of a rectangle is:

P=2L+2W

Where L is the length and W is the width.

2. The length is 100ft more than the width, therefore:

L=W+100

3. Substitute values into the formula for calculate the perimeter and solve for the width:

1260=2(W+100)+2W\\ W=265ft

3. Then, the length is:

L=265ft+100ft\\ L=365ft

The answer is: The length is 365ft and the width is 265ft

5 0
3 years ago
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