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2 years ago

Find the measure of the missing side

Mathematics

2 answers:

Thepotemich [5.8K]2 years ago

8 0

Answer:

10.3

Step-by-step explanation:

a^2 + b^2 = c^2

3.9^2 + b^2 = 11^2

b^2 = 121 - 15.21

b = 10.3

Butoxors [25]2 years ago

3 0

Answer:

10.3

Step-by-step explanation:

We use the pythagorean theorem. (a^2+b^2=c^2)

3.9^2 + b^2 = 11^2

3.9^2 = 15.21

11^2 = 121

15.21 + b^2 = 121

Subtract 15.21 from both sides

b^2=105.79

Take the square root of both sides

b = 10.28

10.28 is closest to 10.3 and it is also rounded to 10.3, therefore 10.3 is the answer.

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Solve each quadratic equation by factoring and using the zero product property.

Iteru [2.4K]

Answer:

x=5 x=6

Step-by-step explanation:

x^2 - 8x + 30 = 3x

Subtract 3x from each side

x^2 - 8x-3x + 30 = 3x-3x

x^2 - 11x + 30 = 0

What 2 numbers multiply to 30 and add to -11

-5*-6 = 30

-5+-6 = -11

(x-5) (x-6) =0

Using the zero product property

x-5 = 0 and x-6 =0

x-5+5 =0+5 and x-6+6 =0+6

x=5 x=6

7 0

3 years ago

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10 to the power of 16 times 10 to the power of -3

rodikova [14]

Answer:

the answer is the Scientific notation of 1×10^13

3 0

2 years ago

PLEASE HELP IM STUCK PLS

tankabanditka [31]

Answer:

y is equal to -16

6 0

1 year ago

Read 2 more answers

Which pair of funtions is not a pair of inverse functions? please help!!

antiseptic1488 [7]

Answer:

$f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Step-by-step explanation:

we know that

To find the inverse of a function, exchange variables x for y and y for x. Then clear the y-variable to get the inverse function.

we will proceed to verify each case to determine the solution of the problem

case A) $f(x)=\frac{x+1}{6} , g(x)=6x-1$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y+1}{6}$

Isolate the variable y

$6x=y+1$

$y=6x-1$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=6x-1$

therefore

f(x) and g(x) are inverse functions

case B) $f(x)=\frac{x-4}{19} , g(x)=19x+4$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y-4}{19}$

Isolate the variable y

$19x=y-4$

$y=19x+4$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=19x+4$

therefore

f(x) and g(x) are inverse functions

case C) $f(x)=x^{5}, g(x)=\sqrt[5]{x}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=y^{5}$

Isolate the variable y

fifth root both members

$y=\sqrt[5]{x}$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=\sqrt[5]{x}$

therefore

f(x) and g(x) are inverse functions

case D) $f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y}{y+20}$

Isolate the variable y

$x(y+20)=y$

$xy+20x=y$

$y-xy=20x$

$y(1-x)=20x$

$y=20x/(1-x)$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=20x/(1-x)$

$\frac{20x}{1-x}\neq \frac{20x}{x-1}$

therefore

f(x) and g(x) is not a pair of inverse functions

7 0

2 years ago

Read 2 more answers

Of the town's 42 firefighters, 16 volunteered for the special rescue team. Express the portion who did not volunteer.

Doss [256]

42 firefighters in total.

16 volunteered for the special rescue team.

n + 16 = 42

or it could be this way:

42 - 16 = n

8 0

3 years ago