What operation should you use to solve -6

Mathematics

1 answer:

Ludmilka [50]2 years ago

8 0

You should do negative

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Determine the value of x. A. 4√2 B. 2/√2 C. 2√2 D. 2

ZanzabumX [31]

Answer:

$\huge\boxed{\sf C.}$

Step-by-step explanation:

sin 45 = opposite / hypotenuse

Where opposite = x , hypotenuse = 4

sin 45 = x / 4

$\sf \frac{\sqrt{2} }{2 } = \frac{x}{4} \\\\x = \frac{4\sqrt{2} }{2} \\\\x = 2\sqrt{2} \\\\\rule[225]{225}{2}$

Hope this helped!

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3 years ago

Consider the following set of data:

Marrrta [24]

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4 0

2 years ago

Finding the inverse of the function x^3+3x+1 is beyond the scope of this course. Nevertheless, you should be able to use your kn

slega [8]

Step-by-step explanation:

${x}^{3} + 3x + 1 = 1 = = = > \\ {x}^{3} + 3x = 0 = = = > \\ x({x}^{2} + 3) = 0 \\ x = 0 \: or \\ {x}^{2} + 3 = 0 = = = > \\ {x}^{2} = - 3 = = = > x 1= \sqrt{ - 3} \: or \: i \sqrt{3} \\ x2 = - \sqrt{ - 3} = = = > x2 = - i \sqrt{3}$

${x}^{3} + 3x + 1 = 5 = = = > \\ {x}^{3} + 3x - 4 = = = > \\ (x - 1)( {x}^{2} + x + 4) = 0 = = = > \\ x - 1 = 0 = = > x1 = 1 \\ {x}^{2} + x + 4 = 0 = = = > \\ x2 = - 1 + i \sqrt{3} \\ x3 = - 1 - i \sqrt{3}$