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Vera_Pavlovna [14]
3 years ago
5

Find the measure of the angle. (final)

Mathematics
1 answer:
ivanzaharov [21]3 years ago
3 0

Answer:

39˚

Step-by-step explanation:

The whole thing is a right angle, and we know that because of the square thing at the top.

These two angles are complementary, so we can subtract 51 from 90.

90-51=39˚

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Find the z-score such as 88% of the area under the normal curve is to the left of the z-score
jok3333 [9.3K]
If you have a calculator with statistical functions, that's the way to go.

On my TI-83, I typed in  invNorm(0.88) and got the result z = 1.17.

88% of the area under the normal curve is to the left of z = 1.17.
6 0
3 years ago
14. A boy completes a 100 m circular track race in 5 min. Another boy runs in the same
Aleksandr [31]

Answer:

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Step-by-step explanation:

5 0
3 years ago
PLEASE HELP ASAP!!!!!!!!!!!
irina [24]

Answer:

132 in^2 but DOUBLE CHECK MY WORK!!!!

Step-by-step explanation:

Break it down into parts ok. So I see a 10x10 square, two 2x4 right triangles and a 4x6 rectangle.

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7 0
3 years ago
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gtnhenbr [62]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
Read 2 more answers
A store sold 2.5 times as many footballs as basketballs last year. What is the number of footballs sold for every basketball sol
bixtya [17]

Answer:

Step-by-step explanation:

You aren't able to figure out an exact number of either footballs or basketballs because you don't have enough information for that, but you do have enough to get an expression for one in terms of the other, which I imagine is the point here.  We know that for every 1 basketball sold, we sold 2.5 footballs, so the algebraic expression for that is

1 bball = 2.5 fballs

This gives us the number of bballs in terms of fballs but we want the number of fballs in terms of bballs, so solve that expression for fballs:

1 fball = 1/2.5 bballs

or, in words, for every single football sold, 2/5 of a basketball was sold.  Sounds silly, but I think your teacher is trying to get you to figure out how to express one thing in terms of another so you can use the expressions in solving story problems.

:/

6 0
3 years ago
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