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Delicious77 [7]
3 years ago
15

Consider the following. y = 2xe−x, y = 0, x = 3; about the y-axis (a) Set up an integral for the volume V of the solid obtained

by rotating the region bounded by the given curve about the specified axis. V = 0 dx (b) Use your calculator to evaluate the integral correct to five decimal places.
Mathematics
1 answer:
IrinaK [193]3 years ago
7 0

Using the shell method, the volume would be

\displaystyle2\pi\int_0^3x(2xe^{-x})\,\mathrm dx=4\pi\int_0^3x^2e^{-x}\,\mathrm dx

Each shell contributes a volume of approximately 2πrh, where r is the distance from the axis of revolution to the shell (<em>x</em>) and h is the height of the shell given by the vertical distance between <em>y</em> = 2<em>x</em> e^(-<em>x</em>) and <em>y</em> = 0.

If you go on to use your calculator, you'll find the volume is approximately 14.49681.

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