We plug in 14 for x when we set the two equations equal to each other to prove they are equal.
So true LM congruent to MN
Answer:
<em>Would be the answer D(1, −4) </em>
Step-by-step explanation:
<em>Excuse me if i'm wrong, it seems like you have the same test or almost. And this was the answer on mine. I hope it works out for you!</em>
Hi there!
It depends on how many colors of gumballs there are and how many gumballs there are in total. With those, we can set the fraction to each gumball color.
Hope this helps!
Answer:
54
Step-by-step explanation:
To solve problems like this, always recall the "Two-Tangent theorem", which states that two tangents of a circle are congruent if they meet at an external point outside the circle.
The perimeter of the given triangle = IK + KM + MI
IK = IJ + JK = 13
KM = KL + LM = ?
MI = MN + NI ?
Let's find the length of each tangents.
NI = IJ = 5 (tangents from external point I)
JK = IK - IJ = 13 - 5 = 8
JK = KL = 8 (Tangents from external point K)
LM = MN = 14 (Tangents from external point M)
Thus,
IK = IJ + JK = 5 + 8 = 13
KM = KL + LM = 8 + 14 = 22
MI = MN + NI = 14 + 5 = 19
Perimeter = IK + KM + MI = 13 + 22 + 19 = 54
72 divides by 9 is 8 so 2 times 8 is sixteen so that would be the answer