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3 years ago

14

Write the point-slope form of the given line that passes through the points (0, -3) and (4, 1). Identify (x1, y1) as (0, -3). In

clude your work in your final answer. Type your answer in the box provided or use the upload option to submit your solution.

1 answer:

ikadub [295]3 years ago

8 0

X1=0
Y1=-3
X2=4
Y2=1
Slop=(y2-y1)/(x2-x1)
Slop=(1-(-3))/(4-0)
Slop=4/4
Slop=1

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Elaina Kicks A Soccer Ball With An Initial Velocity Of

VladimirAG [237]

By using the motion equations, we conclude that she will make the goal.

<h3>Will she make the goal?</h3>

First, we know that the goal is 20ft away, and the position in x is given by:

$x = 28*cos(58)*t$

Let's find the time in which the ball will travel these 20 ft.

$20 = 28*cos(58)*t$

$(20)/(28*cos(58)) = t = 1.35$

So the horizontal distance is covered in 1.35 seconds, now let's see which is the height of the ball at that time.

The height equation is:

$y = -16*t^2 +28*sin(58)*t$

Evaluating in t = 1.35 we get:

$y = -16*(1.35)^2 +28*sin(58)*1.35\\\\y = 2.9$

And the goal is 5ft tall, so we can conclude that she will make the goal.

If you want to learn more about motion equations:

brainly.com/question/19365526

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5 0

1 year ago

Consider the statement : Congruent triangles are always similar. Which of the following statements is an example of the statemen

swat32

Answer:

Yes, the congruent triangles are always similar. The following statements are applicable

1) Angles are the same, but sides are proportional to eachother.

2) Sides are the same size.

3)Corresponding angles and corresponding sides are congruent.

Step-by-step explanation:

Yes, they are similar.

For two triangles to be similar, it is sufficient if two angles of one triangle are equal to two angles of the other triangle. Note that if two angles of one are equal to two angles of the other triangle, the third angles of the two triangles too will be equal.

If two triangles are congruent then all corresponding sides as well as corresponding angles of one triangle are equal to those of other triangles. This can happen in four cases

1)- when all sides of triangles are equal,

2) - if one side and two angles of one are equal to one side and two angles of other triangle.

3) - if two sides and included angle of one triangle are equal to two sides and included angle of other triangle

4)- if in two right angled triangles, one side and hypotenuse of one triangle are equal to one side and hypotenuse of other triangle.

Observe that for triangles to be similar, we just need all angles to be equal. But for triangles to be congruent, angles as well as sides should be equal.

Hence, while congruent triangles are similar, similar triangles may not be congruent ( but the converse is not true) .

4 0

3 years ago

Lauren is making muffins. Her muffin recipe calls for 3 1 −4 cups of flour. She has 10 1 −2 cups of flour. A. Explain a method f

Soloha48 [4]

Answer:

A. 3.2307692308 batches of Muffins

B. 16 1/4 cups of flour

Step-by-step explanation:

Lauren is making muffins. Her muffin recipe calls for 3 1 −4 cups of flour. She has 10 1 −2 cups of flour.

A. Explain a method for determining the number of batches of the muffin recipe Lauren can make. Then use your method to find the number of batches she can make.

Her muffin recipe calls for 3 1 −4 cups of flour. She has 10 1 −2 cups of flour.

3 1/4 cups of flour = 1 batch of Muffin recipe

10 1/2 cups of flour = x

3 1/4 × x = 10 1/2 × 1

x = 10 1/2 ÷ 3 1/4

x = 21/2 ÷ 13/4

x = 21/2 × 4/13

x = 42/13

x = 3.2307692308 batches of Muffins

B. If Lauren plans to make 5 batches of the muffin recipe, use what you know about operating with rational numbers to predict the amount of flour she needs. Justify your prediction.

3 1/4 cups of flour = 1 batch of Muffin recipe

Hence,

1 batch = 3 1/4 cups of flour

5 batches = x

Cross Multiply

x = 5 × 3 1/4 cups of flour

x = 5 × 13/4

x = 65/4

x = 16 1/4 cups of flour

6 0

3 years ago

Help me on this please

zalisa [80]

Answer:

1. (x, y) → (x + 3, y - 2)

Vertices of the image

a) (-2, - 3)

b) (-2, 3)

c) (2, 2)

2. (x, y) → (x - 3, y + 5)

Vertices of the image

a) (-3, 2)

b) (0, 2)

c) (0, 4)

d) (2, 4)

3. (x, y) → (x + 4, y)

Vertices of the image

a) (-1, -2)

b) (1, -2)

c) (3, -2)

4. (x, y) → (x + 6, y + 1)

Vertices of the image

a) (1, -1)

b) (1, -2)

c) (2, -2)

d) (2, -4)

e) (3, -1)

f) (3, -3)

g) (4, -3)

h) (1, -4)

5. (x, y) → (x, y - 4)

Vertices of the image

a) (0, -2)

b) (0, -3)

c) (2, -2)

d) (2, -4)

6. (x, y) → (x - 1, y + 4)

Vertices of the image

a) (-5, 3)

b) (-5, -1)

c) (-3, 0)

d) (-3, -1)

Explanation:

To identify each <u><em>IMAGE</em></u> you should perform the following steps:

List the vertex points of the preimage (the original figure) as ordered pairs.

Apply the transformation rule to every point of the preimage

List the image of each vertex after applying each transformation, also as ordered pairs.

<u>1. (x, y) → (x + 3, y - 2)</u>

The rule means that every point of the preimage is translated three units to the right and 2 units down.

Vertices of the preimage Vertices of the image

a) (-5,2) (-5 + 3, -1 - 2) = (-2, - 3)

b) (-5, 5) (-5 + 3, 5 - 2) = (-2, 3)

c) (-1, 4) (-1 + 3, 4 - 2) = (2, 2)

<u>2. (x,y) → (x - 3, y + 5)</u>

The rule means that every point of the preimage is translated three units to the left and five units down.

Vertices of the preimage Vertices of the image

a) (0, -3) (0 - 3, -3 + 5) = (-3, 2)

b) (3, -3) (3 - 3, -3 + 5) = (0, 2)

c) (3, -1) (3 - 3, -1 + 5) = (0, 4)

d) (5, -1) (5 - 3, -1 + 5) = (2, 4)

<u>3. (x, y) → (x + 4, y)</u>

The rule represents a translation 4 units to the right.

Vertices of the preimage Vertices of the image

a) (-5, -2) (-5 + 4, -2) = (-1, -2)

b) (-3, -5) (-3 + 4, -2) = (1, -2)

c) (-1, -2) (-1 + 4, -2) = (3, -2)

<u>4. (x, y) → (x + 6, y + 1)</u>

Vertices of the preimage Vertices of the image

a) (-5, -2) (-5 + 6, -2 + 1) = (1, -1)

b) (-5, -3) (-5 + 6, -3 + 1) = (1, -2)

c) (-4, -3) (-4 + 6, -3 + 1) = (2, -2)

d) (-4, -5) (-4 + 6, -5 + 1) = (2, -4)

e) (-3, -2) (-3 + 6, -2 + 1) = (3, -1)

f) (-3, -4) (-3 + 6, -4 + 1) = (3, -3)

g) (-2, -4) (-2 + 6, -4 + 1) = (4, -3)

h) (-2, -5) (-2 + 3, -5 + 1) = (1, -4)

<u>5. (x, y) → (x, y - 4)</u>

This is a translation four units down

Vertices of the preimage Vertices of the image

a) (0, 2) (0, 2 - 4) = (0, -2)

b) (0,1) (0, 1 - 4) = (0, -3)

c) (2, 2) (2, 2 - 4) = (2, -2)

d) (2,0) (2, 0 - 4) = (2, -4)

<u>6. (x, y) → (x - 1, y + 4)</u>

This is a translation one unit to the left and four units up.

Vertices of the pre-image Vertices of the image

a) (-4, -1) (-4 - 1, -1 + 4) = (-5, 3)

b) (-4 - 5) (-4 - 1, -5 + 4) = (-5, -1)

c) (-2, -4) (- 2 - 1, -4 + 4) = (-3, 0)

d) (-2, -5) (-2 - 1, -5 + 4) = (-3, -1)

8 0

2 years ago

This hanger is in balance. There are two labels weight. What is the weight of each circle on grams?

Citrus2011 [14]

Answer:

since there is no image attached I can't see what weight they could be labeled but since the scale is even the weights must be the same number weight

Step-by-step explanation:

hope this helped!

6 0

2 years ago