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erma4kov [3.2K]

3 years ago

8

A profesional basketball court is in the shepe of a rectangle. it 50 feet wide and 94 feed long. A player runs one time around t

he edge of the court. How far does the player player run

1 answer:

Serggg [28]3 years ago

4 0

The player ran 288 feet

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PLEASE ANSWER 8TH GRADE MATH QUESTION!

Alina [70]

Wanna show a picture first

4 0

3 years ago

Bob is doing a quality test on machine bots , he tested 24 bolts that he randomly found that 5 were defective. Based on bob’s re

goldenfox [79]

Answer:

175

Step-by-step explanation:

5/24 = 0.208 percentage of defective bolts

scale up to 840 bolts by finding 20.8% of defective bolts

840*20.8 = 175

5 0

2 years ago

What is the coefficient of x2y3 in the expansion of (2x + y)5?

Zigmanuir [339]

Option C:

The coefficient of $x^{2} y^{3}$ is 40.

Solution:

Given expression:

$(2 x+y)^{5}$

Using binomial theorem:

$(a+b)^{n}=\sum_{i=0}^{n}\left(\begin{array}{l}n \\i\end{array}\right) a^{(n-i)} b^{i}$

Here $a=2 x, b=y$

Substitute in the binomial formula, we get

$(2x+y)^5=\sum_{i=0}^{5}\left(\begin{array}{l}5 \\i\end{array}\right)(2 x)^{(5-i)} y^{i}$

Now to expand the summation, substitute i = 0, 1, 2, 3, 4 and 5.

$$=\frac{5 !}{0 !(5-0) !}(2 x)^{5} y^{0}+\frac{5 !}{1 !(5-1) !}(2 x)^{4} y^{1}+\frac{5 !}{2 !(5-2) !}(2 x)^{3} y^{2}+\frac{5 !}{3 !(5-3) !}(2 x)^{2} y^{3}$

$$+\frac{5 !}{4 !(5-4) !}(2 x)^{1} y^{4}+\frac{5 !}{5 !(5-5) !}(2 x)^{0} y^{5}$

Let us solve the term one by one.

$$\frac{5 !}{0 !(5-0) !}(2 x)^{5} y^{0}=32 x^{5}$

$$\frac{5 !}{1 !(5-1) !}(2 x)^{4} y^{1} = 80 x^{4} y$

$$\frac{5 !}{2 !(5-2) !}(2 x)^{3} y^{2}= 80 x^{3} y^{2}$

$$\frac{5 !}{3 !(5-3) !}(2 x)^{2} y^{3}= 40 x^{2} y^{3}$

$$\frac{5 !}{4 !(5-4) !}(2 x)^{1} y^{4}= 10 x y^{4}$

$$\frac{5 !}{5 !(5-5) !}(2 x)^{0} y^{5}=y^{5}$

Substitute these into the above expansion.

$(2x+y)^5=32 x^{5}+80 x^{4} y+80 x^{3} y^{2}+40 x^{2} y^{3}+10 x y^{4}+y^{5}$

The coefficient of $x^{2} y^{3}$ is 40.

Option C is the correct answer.

5 0

2 years ago

Which equation, when solved, results in a different value of x than the other three?

kicyunya [14]

I would have to say -7(1/8)x-4/3=20.

The first and the second one both result in
-23 5/7

The last one results in -24 8/21

but the third one is -22 3/8.

So your answer is either the third of the last one. I assumed the third because, it is lower than all others and the first two are closer to 24 than they are to 22. It’s your choice on how to judge it.

5 0

2 years ago

The odds that a book will be favourable reviewed by three independent critic. a b and c are 5 to 2, 4 to 3 and 3 to 4 respective

Lelu [443]

Answer:

1/4

Step-by-step explanation:

i think you would add 5+4+3 and 2+3+4 and divide them so 9/12 and that makes your probability which leaves a 3/12 chance non of them are in favour of the book

6 0

2 years ago