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3 years ago

Solve the following equation: x2 = 64 x = 32 X = 8 x = -8 x = 8 or x = -8

Mathematics

1 answer:

zepelin [54]3 years ago

8 0

Answer:

X=±8

Step-by-step explanation:

x²=64

x²=8²

X=±✓8²

X=±8

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21 − 3 ) ÷ 32 =<br> 72 × ( 6 ÷ 3 ) =<br> 17 + 15 ÷ 3 − 24 =<br> ( 8 + 56 )÷ 4 − 32 =

Vadim26 [7]

1. 0.5625
2. 144
3. -2
4. -16

3 0

3 years ago

A sprinkler sprays water in a circular area up to 30 feet. A radius reduction screw lets people reduce the radius by up to 25%.

tankabanditka [31]

Answer: $1590.63\ ft^2$

Step-by-step explanation:

Given

The sprinkler can water the area up to $30\ ft$ i.e. $30\ ft$ is the radius

If the screw leads to a reduction of 25% in radius, then the new radius is

$r'=(1-0.25)r\\r'=0.75r\\r'=22.5\ ft$

So, the area corresponding to this radius

$\Rightarrow \pi (22.5)^2\\\Rightarrow 1590.63\ ft^2$

Thus, the maximum area that can be covered is $1590.63\ ft^2$

5 0

3 years ago

The mean of 3, a+2, 8, 12, 2a-1 and 6 is 7. Find the value of a. its urgent plsss

Anarel [89]

Answer:

5.5

Step-by-step explanation:

4 0

3 years ago

The sum of the 4 digit numbers ABCD and DCBB is a multiple of 10.

Nady [450]

The difference between the numbers ABCD and DCBB is 10000

<h3>How to determine the difference</h3>

From the information given, we have that:

ABCD and DCBB is a multiple of 10.

The digits A,B,C and D are consecutive integers

The number ABCD is a multiple of 3

We can say that:

B + D = 10

A = 3

B = 4

C = 5

D = 6

Now,

ABCD = 3456

DCBB = 6544

Difference between the numbers ABCD and DCBB = 3456 + 6544 = 10, 000

Thus, the difference between the numbers ABCD and DCBB is 10000

Learn more about word problems here:

brainly.com/question/13818690

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7 0

1 year ago

Simplify 2 to the fifth power over 3 squared all raised to the fourth power. 2 to the twentieth power over 3 to the eighth power

Murrr4er [49]

2 to the fifth power over 3 squared all raised to the fourth power

$\left(\dfrac{2^5}{3^2}\right)^4=\dfrac{(2^5)^4}{(3^2)^4}=\dfrac{2^{5\cdot4}}{3^{2\cdot4}}=\dfrac{2^{20}}{3^8}$

Answer: 2 to the twentieth power over 3 to the eighth power

Used:

$\left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\\\\(a^n)^m=a^{n\cdot m}$

7 0

3 years ago