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3 years ago

Write (26 + 16i) − (26 − 7i) as a complex number in standard form.

Mathematics

2 answers:

ValentinkaMS [17]3 years ago

5 0

The answer would be 23i.

Simplify ( 26 + 16i - 26 + 7i )

Gather like terms ( 26 - 26 ) + (16i + 7i)

Simplify (23i)

Maksim231197 [3]3 years ago

4 0

Answer: The required standard form of the complex number is $0+23i.$

Step-by-step explanation: We are given to write the following complex expression as a complex number in standard form :

$E=(26+16i)-(26-7i)~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

We know that

a complex can be written in standard form as follows :

$z=a+bi,$ where a and b are real numbers.

From (i), we have

$E\\\\=(26+16i)-(26-7i)\\\\=(26-26)+(16+7)i\\\\=0+23i.$

Thus, the required standard form of the complex number is $0+23i.$

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