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lapo4ka [179]
3 years ago
10

Write (26 + 16i) − (26 − 7i) as a complex number in standard form.

Mathematics
2 answers:
ValentinkaMS [17]3 years ago
5 0
The answer would be 23i.

Simplify ( 26 + 16i - 26 + 7i )

Gather like terms ( 26 - 26 ) + (16i + 7i)

Simplify (23i)
Maksim231197 [3]3 years ago
4 0

Answer:  The required standard form of the complex number is 0+23i.

Step-by-step explanation:  We are given to write the following complex expression as a complex number in standard form :

E=(26+16i)-(26-7i)~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

We know that

a complex can be written in standard form as follows :

z=a+bi,  where a and b are real numbers.

From (i), we have

E\\\\=(26+16i)-(26-7i)\\\\=(26-26)+(16+7)i\\\\=0+23i.

Thus, the required standard form of the complex number is 0+23i.

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Answer:

A person in a group where 5 people are sharing 3 small bags of snickers

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Let the number of calories in one bag of snickers =x

Number of calories in 3 small bags of snickers =3x

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We then compare the two.

Let x=1

\dfrac{3}{5}=0.6$ calories per person\\\dfrac{2}{7}=0.29$ calories per person

Therefore, a person in a group where 5 people are sharing 3 small bags of snickers gets more calories.

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