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lapo4ka [179]
3 years ago
10

Write (26 + 16i) − (26 − 7i) as a complex number in standard form.

Mathematics
2 answers:
ValentinkaMS [17]3 years ago
5 0
The answer would be 23i.

Simplify ( 26 + 16i - 26 + 7i )

Gather like terms ( 26 - 26 ) + (16i + 7i)

Simplify (23i)
Maksim231197 [3]3 years ago
4 0

Answer:  The required standard form of the complex number is 0+23i.

Step-by-step explanation:  We are given to write the following complex expression as a complex number in standard form :

E=(26+16i)-(26-7i)~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

We know that

a complex can be written in standard form as follows :

z=a+bi,  where a and b are real numbers.

From (i), we have

E\\\\=(26+16i)-(26-7i)\\\\=(26-26)+(16+7)i\\\\=0+23i.

Thus, the required standard form of the complex number is 0+23i.

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I need help!
arsen [322]

The instantaneous rate of change of the function f(x) = −4x² − 3x + 1 at the point x = -3 is 21.

<h3>What is the instantaneous rate of change of the function at the given point?</h3>

The instantaneous rate of change is simply the change in the derivative value at a specific point.

Given the data in the question;

  • f(x) = −4x² − 3x + 1
  • Point x = -3

To determine the instantaneous rate of change of the function, first find the derivative of the function.

f(x) = −4x² − 3x + 1

Applying sum rule, with respect to x

d/dx[ -4x² ] + d/dx[ -3x ] + d/dx[ 1 ]

[ 2 × -4x¹ ] + [ 1 × -3x⁰ ] + d/dx[ 1 ]

[ -8x ] + [ -3 ] + d/dx[ 1 ]

-8x - 3 + d/dx[ 1 ]

Differentiate using constant rule

-8x - 3 + [ 0 ]

-8x - 3

f'(x) = -8x - 3

Next, plug x = -3 into the derivative and simplify.

f'(x) = -8x - 3

f'(-3) = -8(-3) - 3

f'(-3) = 24 - 3

f'(-3) = 21

Therefore, the instantaneous rate of change of the function f(x) = −4x² − 3x + 1 at the point x = -3 is 21.

Learn more about instantaneous rate of change here: brainly.com/question/28122560

#SPJ1

7 0
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