Answer:
1. Radius 18in Diameter 38in Circumference 36in
2. Radius 9in Diameter 34in Circumference 18in
3. Radius 6in Diameter 36in Circumference 12in
4. Radius 7in Diameter 26in Circumference 14in
5. Radius 5in Diameter 8in Circumference 10in
6. Radius 11in Diameter 33in Circumference 22in
7. Radius 6in Diameter 20in Circumference 12in
8. Radius 7in Diameter 16in Circumference 14in
9. Radius 2in Diameter 12in Circumference 4in
Step-by-step explanation:
Tip: When finding the circumference of a circle, just multiply the radius by 2!
Hope I get my brainliest even tho I couldn't get all of it!
Answer:
Step-by-step explanation:
The given absolute value function is
This is the base or the parent function.
The transformation 
will shift the parent function b units to the left and c units up.
From the question, b=4 units and c=2 units.
The new equation is
Answer:
D
Step-by-step explanation:
So we have the equation:
And we want to solve for x.
We can solve it by completing the square.
First, subtract 58 from both sides:
Divide the b term by 2 and square it:
So, add 9 to both sides:
On the left, the perfect square trinomial pattern. Add on the right. So:
Take the square root of both sides:
The square root of -49 is 7i:
Add 3 to both sides:
So, our answer is D.
And we're done!
First things first.. What type of triangle
If u are taking about a normal triangle here is some:
∠60+∠60+∠60
∠30+∠90+∠60
∠11+∠82+∠87
Hello!
Here are some rules to determine the number of significant figures.
- Numbers that are not zero are significant (45 - all are sigfigs)
- Zeros between non-zero digits are significant (3006 → all are sigfigs)
- Trailing zeros are not significant (0.067 → the first two zeros are not sigfigs)
- Trailing zeros after a decimal point are always significant (1.000 → all are sigfigs)
- Trailing zeros in a whole number are not significant (7800 → the last two zeros are not sigfigs)
- In scientific notation, the exponential digits are not significant, known as place holders (6.02 x 10² → 10² is not a sigfig)
Now, let's find the number of significant figures in each given number.
A). 296.54
Since these digits are all <em>non-zero</em>, there are 5 significant figures.
B). 5003.1
Since the two <em>zeros are between non-zero digits</em>, they are significant figures. Thus, there are 5 significant figures.
C). 360.01
Again, the two zeros are between non-zero digits. There are 5 significant figures.
D). 18.3
All of these digits are non-zero, hence, there are 3 significant figures.
Therefore, expression D has the fewest number of significant figures being 3.
